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Physics: Post your doubts here!

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According to the equation n*lamda=d*sin theta
n is 3.33 so 3 images from X to Y, 3 from Y to Z and 1 zero order at Y so total 7.

Well, how did you calculate the value of theta, I mean i didn't how to find n,
I was trying on d sin theta = n lamda,
I found out d but couldn't figure out the value of theta:/
 
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How is the answer D?

5 A quantity x is to be determined from the equation
x = P – Q.
P is measured as 1.27 ± 0.02 m.
Q is measured as 0.83 ± 0.01 m.
What is the percentage uncertainty in x to one significant figure?
A 0.4 % B 2 % C 3 % D 7 %
 
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How is the answer D?

5 A quantity x is to be determined from the equation
x = P – Q.
P is measured as 1.27 ± 0.02 m.
Q is measured as 0.83 ± 0.01 m.
What is the percentage uncertainty in x to one significant figure?
A 0.4 % B 2 % C 3 % D 7 %
P-Q=1.27-0.83=0.44
but unceritnities always add up
sp 0.02+0.02=0.03
(0.03/0.44)*100
is the answer D
 
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25 A wire stretches 8 mm under a load of 60 N.
A second wire of the same material, with half the diameter and a quarter of the original length of
the first wire, is stretched by the same load.
Assuming that Hooke’s law is obeyed, what is the extension of this wire?
A 1 mm B 4 mm C 8 mm D 16 mm
 
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How is the answer D?

5 A quantity x is to be determined from the equation
x = P – Q.
P is measured as 1.27 ± 0.02 m.
Q is measured as 0.83 ± 0.01 m.
What is the percentage uncertainty in x to one significant figure?
A 0.4 % B 2 % C 3 % D 7 %
well, when you subtract 1.27 and 0.83, you get 0.44. However, you always add the uncertainties. you never subtract them just because the values are being subtracted. So when you add 0.02 and 0.01 and get 0.03, divide 0.03 by 0.44 *100 and you should get around 7%
 
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