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no idea u can use http://maxpapers.com/Can anyone tell me why is the papers webpage not working, it is saying that the webpage is not available, this is the site papers.xtremepapers.com
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I just want to know the pattern produced in the tube and C PART???
thnk u so much............MA ure a very competent teacher ....The wavelength is 60 cm, but the tube length is 45 cm.
45 cm is 3/4th of 60 cm. Which means that it is 3/4th the wavelength.
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Where I put "AN", you're supposed to write A.
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As the frequency is decreased, the wavelength will increase, because v = f(lambda). Right now the wavelength is 60 cm. So as we decrease our frequency, we need to end up with a wavelength that is >60 cm. This is simply to check whether our final answer makes sense.
For a sound to be produced in an open tube, there must be an antinode at the open end, and a node at the closed end. The only two wavelengths that support this are:
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1/4th lambda and 3/4th lambda are both the lengths of the tube. Since 1/4th lambda is the smallest length required for a sound to be produced we can form an equation relating the length and lambda.
Length of tube = lambda / 4
Lambda = Length of tube * 4
They mention in part c that the length is going to remain 45 cm,
So lambda is 45 cm * 4 = 180 cm.
Plug this value of the wavelength into the wave equation, v = f(lambda)
330 = f * (180/100), since the speed is in "metres" per second.
f = 330/1.8
f = 183.333.... Hz which rounds down to 180 Hz. However, you're most welcome to leave your answer as 183.
Hope that made sense, if you're still confused, let me know
thank you soo much.
so basically the formula used is of the area .. right?
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how to do the part (2) of (b) ?Cant we subtract the distance 100 -79=21cm and then find the interval between then ...whereas in markscheme distance of 90cm is used and interval of time found in part 1 is subtracted from it .....can somebody explain WHY?? wid calculations ???
possible error is 10% and uncertainity is 2% so it can be 10+ or 2 which could be 8 and 12 but maximum error is 10 so value cant exceed 10 which means it has to be 8 and not 12. 8% is error so we can measure (100-8)=92% accurately.Hello guys, could someone please help me in this one, I tried reading the marking scheme multiple times but it didn't help at all.
I am unable to solve 9b
I would appreciate a clear explanation ^_^ THANKS!
Paper: 9702/s09/qp4 Question 9b, page 16
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pressure = F/ACan someone plz help me .. how to derive the formula pressure = density*gravity*height
Phase difference is OTwo loudspeakers both emit sounds with a frequency of 340Hz. Both sounds have equal amplitude and phase. The amplitude is A. The speakers are 4m apart and face each other. (The speed of sound in air is 340ms-1)
Having equal phase means O phase difference or a constant phase difference?
does that mean they are in phase and will ALWAYS interfere constructively?Phase difference is O
• If the distance traveled by the waves from two disturbance is same, then path difference will be zero.does that mean they are in phase and will ALWAYS interfere constructively?
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