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yes, speed = wavelength x frequency
question is asking for frequency i.e number of waves in one second
question is asking for frequency i.e number of waves in one second
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Q15In Q 15 why arent B and C correct,in Q30 why isnt B correct,in Q36 why cant A be correct and Q 39?
thnx broQ15
B :- if thats the case it would go up but its in equilibrium
C:- ok but thats not the reason for upthrust
Q30
draw out the triangle and you will see. u=vcostheta but v = u/costheta.
Q36
Its a constant voltage supply. It can only supply a voltage of V
Q39
Nucleon Number of Uranium is 238
Mass of one nucleon is abbt 1.67 x10^-27
Multiply them !
Thanks a lot skypilotage! in my last query what I actually don't get is k why are we not putting "Re" in the place of radius of earth, why X2? I mean why not solve it in terms of "Re". And can you also explain the table of the same paper question 2 part b part 2?Capacitance Ratio is 1 : 2 and each capacitor can hold 6 volt max.
3 Volts 6 Volts
Total = 9 Volts maximum
formula is V= Vmaxsin(omega t)
omega= 2pie f
120pie = 2pie f
f = 120pie/2pie = 60Hz
will solve question 10 later and scan it for you
Because we are using graviatational fields in solving the question. We equate g of Earth = g of Moon with formula GM/x^2.
If you need help solving it tell me and Ill take a photo of it for you.
Because there are two values of X one which is between Earth and Moon and Second is after the moon.Thanks a lot skypilotage! in my last query what I actually don't get is k why are we not putting "Re" in the place of radius of earth, why X2? I mean why not solve it in terms of "Re". And can you also explain the table of the same paper question 2 part b part 2?
For 5(c) iiAS PHYSICS
P2
N 05
Q 4 (b) (ii).
Q 5 (c) (ii)
Q 6 (a)
Q7 (b) (iii)
Q8 (b) (ii)
For 7b(iii)AS PHYSICS
P2
N 05
Q 4 (b) (ii).
Q 5 (c) (ii)
Q 6 (a)
Q7 (b) (iii)
Q8 (b) (ii)
For 5(c) ii
In order to find resultant intensity u will have to find resultant amplitude.So Amplitude of A-amplitude of B=3-2=1
Now u can use either Intensity of A i.e I or intensity of B i.e 4/9I to find resultant intensity.
6a:
Since potential of plates is unknown u have to assume Y is positive cuz then only force will be upwards which will balance the weight of the particle which is a force and acting downwards.Always remember to consider weight i.e mg when solving questions of these type.
ur welcomeTHANK YOU
Q18In Q18 why cant D be correct?
Q)23
In Q27 why cant B be correct?
Q37
Q40
The electrical signal is converted to Pulses of light emitted by a laser or LED of frequency 2x10*8 MHz.in ADC .......why having more bits reduces step height
how information is carried in an optic fiber.....ok its in the form of light....bt i can tvisualise how waht i ll speak can be carried by lkight,.....or how a football match broadcast cn be carried in the form of light
For Q37 if u say the resistance of one wire is 6R then wont total resistance be 6R *6 cuz there are 6 wires in Q?Q18
Work lost is the unshaded area. you dont put work to unstretch a rubberband
Q23
a is max at the peaks, speed is max at the middle
Q27
wrong direction of motion, its a stationary wave. Motion of particles is reflected.
Q37
If it is drawn into 6 wires for example.
The area of one wire in Q is A/6 so Resistance of one wire is 6R since R is inv prop. to A.
So total R is 6R/6 = R i.e same Resistance as P
Q40
the nucleus with the smallest Z/M Ratio has the lowest a i.e Li ratio is the smallest ( 3/7 = 0.428 )
They are in parallel not series! careful!For Q37 if u say the resistance of one wire is 6R then wont total resistance be 6R *6 cuz there are 6 wires in Q?
No because the reading of the metre under the surface measures the pressure that is exerted on it, which is due to both the water and the atmospheric pressure.In Q 18 why do we subtract the pressures shouldnt we add them??
Im not quite good with uncertainities but here goes:-AoA wr wb
if r=3x+y
the uncertainty in r will be = 3Δx + Δy or Δx + Δy
and if r = ((a^3)(b^2)) / (2a+b)
then ΔR = ??
help plz
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