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Physics: Post your doubts here!

shinnyyy

shinnyyy

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Liv2Stdy said:
Work done would be Fs if the car was travelling on a horizontal road but in this case it's not, the car is travelling at angle a and the weight also acts on the inclined plane. You need to break this weight into its components coz the weight also acts at an angle a (look at my diagram). Force F is in the horizontal direction. If you look at the components, mgsina=F.......so even though you exert a force F on the car, due to the weight only a component acts on the car to make it move. Hence, useful energy output becomes mgsina x s.
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Thanks a ton :) now the doubt is cleared , ty ty ty
nd can u help me with biology doubts as well :unsure:
 
shinnyyy

shinnyyy

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Wkhan860 and can you please explain me what's this eV bcoz there are so many questions in new papers and I don't how to solve them as I haven't been taught this thing by my sir.
 
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