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Alhumdulilah lucky uYup I did.....thank god It ddnt cam In exams
ill send u my.notes nd explanation by tonight
thankx
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Alhumdulilah lucky uYup I did.....thank god It ddnt cam In exams
ill send u my.notes nd explanation by tonight
14-
Is 13 B ?
Thankyouuuu14-
Horizontal component of velocity = v cos(45)
Vertical component of velocity = v sin(45)
initial kinetic energy E = 1/2 m v^2
now see the question says KE at highest position which means there wont be vertical velocity as at the highest point vertical v is zero
we only hve horizontal so final KE = 1/2 m (cos 45)^2 v^2
final kinetic energy is 1/2 m 0.5 v^2......this is half of E
hope u got it!
srry....ddnt get the tag
Ah no worries man :') you have already helped me alotsrry....ddnt get the tag
most welcomeThankyouuuu
????Is 13 B ?
Can anyone tell me where to get Topical Mcq's P1 for As-Levels?????
s044/M/J/02 Q.4(b)
6/M/J/02 Q.5(a),Q.14(c),Q.15(a)
When the gain is more than the supply voltage 10>9 V, the op-amp will go into saturation. So, normally you get back the supply voltage.View attachment 55423
The problem is for c(ii)
i use Vout/V in=1 +Rf/R1
Replacing the values Vin=+0.4 , Rf =120 R1=5
i get answer :10 V
But the answer from marking scheme is 9 V . Can someone tell me the Reason ? is it linked to the diagram in part B ?
http://www.physicsclassroom.com/reviews/circuits/circuitsans2.cfm20. Approximately how long would it take an electron to travel from the battery of a car to a head light and back (complete loop)?
a. seconds
b. hours
c. years
d. one-millionth of a second
e. one-tenth of a second
Anyone having topical questions for Alevels phy applications ????
Please reply !!
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