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Physics: Post your doubts here!

R

raamish

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How do we do these questions?
Qs 24 and 27
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s06_qp_1.pdf

Qs 23, 26
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s07_qp_1.pdf

Qs 26,27,28
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s08_qp_1.pdf

Qs 27
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w06_qp_1.pdf

Qs 23,24,25
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w07_qp_1.pdf
 
confused123

confused123

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raamish said:
How do we do these questions?
Qs 24 and 27
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf

Qs 23, 26
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_qp_1.pdf

Qs 26,27,28
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_qp_1.pdf

Qs 27
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w06_qp_1.pdf

Qs 23,24,25
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_1.pdf
Click to expand...
q.24) Intensity directly proporitonal to Amplitude sq. , so 2I direct propo to A^2 , put A^2 instead of I in the place of in 2I.

Now under root 2A^2 = A^2 = 1.4A , frequency halved means half the number of waves will be created. so B


27) more lines or slits per meter so diffraction will increase and the angle between 1st nd 2nd will increase but less numbers of orders will be visible as more diffraction taking place. distance increases between adjacent maximas and minimas. i am not so sure about this explanation.
 
R

raamish

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confused123 said:
q.24) Intensity directly proporitonal to Amplitude sq. , so 2I direct propo to A^2 , put A^2 instead of I in the place of in 2I.

Now under root 2A^2 = A^2 = 1.4A , frequency halved means half the number of waves will be created. so B


27) more lines or slits per meter so diffraction will increase and the angle between 1st nd 2nd will increase but less numbers of orders will be visible as more diffraction taking place. distance increases between adjacent maximas and minimas. i am not so sure about this explanation.
Click to expand...
When u have time plzzz do the rest of the questions
 
confused123

confused123

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raamish said:
How do we do these questions?
Qs 24 and 27
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf

Qs 23, 26
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_qp_1.pdf

Qs 26,27,28
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_qp_1.pdf

Qs 27
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w06_qp_1.pdf

Qs 23,24,25
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_1.pdf
Click to expand...
s07) 23) P is showing us the amplitude as it is a displacement time graph. the displacement at Q can't always be zero as the particle will oscillate upwards and downwards it will not stay stationary. Energy at point R also involves potential energy. so we are only left with option D which has to be CORRECT!

26) i think its D because decreasing wavelngth will result in increase in separation of fringes. Lambda = ax / d

s08) the distance is doubled so amplitude will be halved...rest later
 
confused123

confused123

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s08 27) frequency = velocity over lambda , x is the distance from the wall where a antinode forms. 4 consecutive antinodes will make one wavelength so F = v/ 4x D ans.

28) d sin Q = n lambda , d= 1/N , sin Q = 3 lambda as its the 3rd order into lambda into N , i.e B option .

w06) 27) i don't know.

w07) 23. idk
24) lambda = ax /d , so increasing wavelength will increase the fringe separation as well. D option
25) idk
 
H

hassam

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http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w07_qp_4.pdf​
q2 a (ii)​
here wen finding separation between atoms.....okay....we calculate volume occupied by a single atom......then when taking the cube root aren't we finding the length of the cube assuming cubic atoms...how does this relate to separation between atoms....i never understand this....i mean why is the length of cubic atom also separation between atoms........well likhtay likhtay aik cheex xehn mein ayi....is it because legth of one side is same as the distance between the centres of two adjacent cubic atoms?????​
 
H

hassam

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brother 1 v is the potentIal dropped across the first R AND U R Saying its the potential of non inverting input........................and k if u r ryt then what will hapeen wen switch is closed.....nothing will happen ....polarity will nt be changed.......
 
H

hm12

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when switch open V- is 1.5v V+ is 2.0v if u take gain equal to 10^5 then Vout= 10^5(2.0-1.5)=50 000 to prevent saturation Vout=+9V
when switch is closed V- is 3.0V and V+ is 2.0V then Vout=10^5(2.0-3.0)=-100000V to prevent saturation Vout=-9V
S0 output changes from positive to negative this is what i think the answer should be
 
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