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The radio waves emitted travel a distance 'd' by going from the source to the reflector. And then when reflected they again travel a distance 'd' from the reflector the source. That means that the radio waves travel a total distance of '2d'.
For (b) part you know the distance between source and reflector as calculated before. Also you know the speed of sound which is given. Calculate the time taken using :
thnku so much xDFor (b) part you know the distance between source and reflector as calculated before. Also you know the speed of sound which is given. Calculate the time taken using :
t = 2s/v (the distance will be multiplied by 2 because it sound travels distance 'd' twice from source to reflector and from reflector to source.)
t = 2 * 120 / 300 = 0.8s
We're asked that the separation between the peaks must be same, so divide this time with the number of boxes you counted in the previous part (i.e. 4 boxes). This will give you the time base setting: 0.8/4 = 0.2s/cm
Can you post the whole question?
i dont get thtView attachment 60248
The trace will be something like this^
i dont get tht
For static equilibrium, the resultant force is zero. So the (upward) force in the spring is equal to the total (downward) weight of all the masses.Plz solve
Okaaaay thanksFor static equilibrium, the resultant force is zero. So the (upward) force in the spring is equal to the total (downward) weight of all the masses.
Spring force....T = 0.20 (10) + 0.1 (0.10) = 3N
When the thread is burnt, the weight of the 0.10kg mass no longer contributes any forces to the system, but at that (instant)... the spring force is still 3N.
So, the weight of the 0.20kg acts downwards while the spring force acts upwards. The resultant (upward) force on the 0.20kg mass is given by
Resultant force = ma = T – mg = 3 – 0.20(10) = 1N
Acceleration, a = 1 / 0.20 = 5ms-2
View attachment 60262
part b(ii)
Find the area under the graph upto F = 6.4N
thnx alotFind the area under the graph upto F = 6.4N
work done = area under the graph
= 1/2 * 6.4 * 8 * 10^-2
= 0.256J
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