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Can you post the whole question?
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Can you post the whole question?
i dont get thtView attachment 60248
The trace will be something like this^
i dont get tht
For static equilibrium, the resultant force is zero. So the (upward) force in the spring is equal to the total (downward) weight of all the masses.Plz solve
Okaaaay thanksFor static equilibrium, the resultant force is zero. So the (upward) force in the spring is equal to the total (downward) weight of all the masses.
Spring force....T = 0.20 (10) + 0.1 (0.10) = 3N
When the thread is burnt, the weight of the 0.10kg mass no longer contributes any forces to the system, but at that (instant)... the spring force is still 3N.
So, the weight of the 0.20kg acts downwards while the spring force acts upwards. The resultant (upward) force on the 0.20kg mass is given by
Resultant force = ma = T – mg = 3 – 0.20(10) = 1N
Acceleration, a = 1 / 0.20 = 5ms-2
View attachment 60262
part b(ii)
Find the area under the graph upto F = 6.4N
thnx alotFind the area under the graph upto F = 6.4N
work done = area under the graph
= 1/2 * 6.4 * 8 * 10^-2
= 0.256J
nov 14 p41Which year is this
solve all the past papers of all variantsI'm going to appear for my AS LEVEL exams next month.....can anyone plzzz give me sm tips to score maximum marks in P1
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