Physics: Post your doubts here!

[princess Anu]

Help with bii
j2004

 

[The Sarcastic Retard]

Help with bii
j2004View attachment 60168

Crms is proportional to sqrt(T)
Now solve it.

 

[Saad the Paki]

It depends from person to person. I had a friend who gave 6 subjects in 6 months and scored 6A*s and a friend who is giving just As level since 2 years and yet he is stuck at D. So now as I said, it depends. If you love studying and your complete focus is in studies and wanna score good u need to practice heck so muchhhhhhhhhhhhhhhhhhhhh!!

For me, I think giving As first then A2 is better option as I cant take both load together.
You can give 2 subjects As and A level in november and other 2 in summer and other 2 in next november.. So in just one year you are done with your A levels with 6 subjects, which is so good if u score more than B in it. This is what I think.

Good luck..

You're giving 6 subjects?!

 

[princess Anu]

Crms is proportional to sqrt(T)
Now solve it.

i can't
If I use mean square speed is proportional to T, I get 120 not 1200 :/( which is the answer)
my working is:
<c^2> propotional to T
Since crms is 500 <c^2> must be 500^2 i.e 2500000
So 2500000/300(T) = 8333.3 ( proportionality constant k)
Therefore T2 should be equal to
New <c^2> /k i.e 1000000/8333.3= 120:/

 

[The Sarcastic Retard]

i can't
If I use mean square speed is proportional to T, I get 120 not 1200 :/( which is the answer)
my working is:
<c^2> propotional to T
Since crms is 500 <c^2> must be 500^2 i.e 2500000
So 2500000/300(T) = 8333.3 ( proportionality constant k)
Therefore T2 should be equal to
New <c^2> /k i.e 1000000/8333.3= 120:/

Crms is proportional to sqrt(T)
Crms1/Crms2 = sqrt(T1)/sqrt(T2)
500/1000 = sqrt(300)/sqrt(T2)
T2 = 1200K

 

[The Sarcastic Retard]

You're giving 6 subjects?!

I am giving four. That was my friend who gave 6 subjects.

 

[The Sarcastic Retard]

http://papers.gceguide.com/A Levels/Physics (9702)/9702_s15_qp_43.pdf
Q7
Q8 last theory part
Q9 graph part.

Thanks.

 

[The Sarcastic Retard]

View attachment 60167

?

 

[farhan141]

I think u have to use the Electron Diffraction experiment.

 

[The Sarcastic Retard]

I think u have to use the Electron Diffraction experiment.

What is that? No idea about it.
I dont know what is concentric rings and stuffs, never studied about it.

 

[farhan141]

What is that? No idea about it.
I dont know what is concentric rings and stuffs, never studied about it.

 

[The Sarcastic Retard]

Can I get notes on Hall effect/Hall probe thingy (A2 level)?
Thank you.

 

[The Sarcastic Retard]

View attachment 60181 View attachment 60181 View attachment 60182 View attachment 60183

Thanks a lottttttttttt!! ^_^
Do u have more notes???
This concetric ring I never found in my text book. From where did u get?

Can I get notes on hall probe?

How De broglie wavlength and radius is related?

 

[princess Anu]

Crms is proportional to sqrt(T)
Crms1/Crms2 = sqrt(T1)/sqrt(T2)
500/1000 = sqrt(300)/sqrt(T2)
T2 = 1200K

Thanks
But which formula are you using
Where does it say crms sqrt is proportional to t sqrt

 

[The Sarcastic Retard]

Thanks
But which formula are you using
Where does it say crms sqrt is proportional to t sqrt

Crms = sqrt(3kT/m)
This formula when m is constant Crms is prop. sqrt T

 

[The Sarcastic Retard]

Thanks a lottttttttttt!! ^_^
Do u have more notes???
This concetric ring I never found in my text book. From where did u get?

Can I get notes on hall probe?

How De broglie wavlength and radius is related?

Xylferion
qwertypoiu
Physicist

 

[farhan141]

H

 

[farhan141]

Debroglie wavlength and radius arent related?

 

[Darth Vader]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s10_qp_11.pdf
Question 15. I need the working

 

[The Sarcastic Retard]

Debroglie wavlength and radius arent related?

I gotta know that 2 * pi * r = n * lambda (lambda prop. r)
IDK how this comes from