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Physics: Post your doubts here!

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Explain why the alternating current in the primary coil of a transformer is not in phase with the alternating e.m.f. induced in the secondary coil.

Because the current in the primary coil is in phase with the flux in the core
But not the change in the flux, (change in the flux is not in phase with the flux in the core) ,and it is the change in flux that generates the alternating emf hence we say Alternating Current is not in phase with the Alternating emf
 
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I can't visualise this question
Which part of the needle is oscillating and how is it oscillating( which direction)? why is the amplitude 11mm? + in bi needle should be at its max height, i get it , but why is this max height 14mm below cloth or 8mm above cloth? :(
Can someone draw on the figure and explain
Please



biScreenshot 2016-04-10 13.19.55.png
 
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Because the current in the primary coil is in phase with the flux in the core <-------- How do we know this??
But not the change in the flux. <-------- change is flux wont be generated as we using ac?

So why does change in the flux not in hase with flux in the core.
 
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I can't visualise this question
Which part of the needle is oscillating and how is it oscillating( which direction)? why is the amplitude 11mm? + in bi needle should be at its max height, i get it , but why is this max height 14mm below cloth or 8mm above cloth? :(
Can someone draw on the figure and explain
Please



biView attachment 60196
No one solved my this doubt. I had the same doubt a month ago. :)
 
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Because the current in the primary coil is in phase with the flux in the core <-------- How do we know this??
But not the change in the flux. <-------- change is flux wont be generated as we using ac?

So why does change in the flux not in hase with flux in the core.
Im also confused with this bs. I have not studied it anywhere that this happens but in marking scheme they have explained as if we know it.
 
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Can someone please explain this question? Answer is D

View attachment 60213
When two objects have an elastic collision, the relative speed of approach is equal to the relative speed of separation.
When two objects are moving towards each others, the relative speed of one object relative to the other is given by sum of the speeds of two objects. So relative speed of appraoch here is u1 + u2.

When two objects are moving in a same direction, then the relative speed of an object is calculated by subtracting the individual speeds of the two objects. So the relative speed of separation here is given by: v2-v1

As stated above: "When two objects have an elastic collision, the relative speed of approach is equal to the relative speed of separation. ", the equation for this situation will become:

u1 + u2 = v2 - v1

So answer is D.
 
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When two objects have an elastic collision, the relative speed of approach is equal to the relative speed of separation.
When two objects are moving towards each others, the relative speed of one object relative to the other is given by sum of the speeds of two objects. So relative speed of appraoch here is u1 + u2.

When two objects are moving in a same direction, then the relative speed of an object is calculated by subtracting the individual speeds of the two objects. So the relative speed of separation here is given by: v2-v1

As stated above: "When two objects have an elastic collision, the relative speed of approach is equal to the relative speed of separation. ", the equation for this situation will become:

u1 + u2 = v2 - v1

So answer is D.
Is this method valid only when the masses of the 2 objects are equal or whenever there is an elastic collision?
 
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When two objects have an elastic collision, the relative speed of approach is equal to the relative speed of separation.
When two objects are moving towards each others, the relative speed of one object relative to the other is given by sum of the speeds of two objects. So relative speed of appraoch here is u1 + u2.

When two objects are moving in a same direction, then the relative speed of an object is calculated by subtracting the individual speeds of the two objects. So the relative speed of separation here is given by: v2-v1

As stated above: "When two objects have an elastic collision, the relative speed of approach is equal to the relative speed of separation. ", the equation for this situation will become:

u1 + u2 = v2 - v1

So answer is D.

Im still confused. When the objects are approaching, they are in different directions and when they're separating, they go in the same direction. so why not A?
 
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