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Physics: Post your doubts here!

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9702/22/M/J/11 Q2(b)(ii)

A second raindrop has a radius that is smaller than that given in (a). On Fig 2.1, sketch the variation of speed with time for this second raindrop

The sketch is below the original curve

Is it because the radius is smaller therefore the mass is smaller as well (since p=mv) so it reaches terminal velocity earlier?
Terminal velocity occurs when the weight of an object is equal to the air resistance acting on it. An object with smaller mass has lesser weight and hence less air resistance will be required to achieve terminal velocity. Your explanation is correct.
 
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The two changes that will occur will be the change in speed of the meteorite since the combined gravitational field of both will cause the meteorite to accelerate and also the meteorite will deviate from the path it would have followed otherwise in the absence of the second field.
The decay might occur while you are taking measurements since the half life is so small therefore it isn't suitable.
 
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I dont have the MS for these so can someone verify the circled part and solve for part b in the other photo?
 

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Part c anyone?
 

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Part c anyone?
Gain = V out / V in -----------> V out = V in x Gain -------> V out = 95x10^-3 * 71 = 6.75 V

If you chose +/- 5V as your power supply, 6.75 is over that limit. This results in saturation, which when you plot a graph of Voltage/Time, will clip the values beyond 5V.

You don't want this, so you pick the power supply that wont clip the values, which in this case is the +/- 9V supply.

Screen Shot 2016-04-09 at 4.11.44 AM.png
 
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i have qtn...is giving AS better or giving the complete A LEVEL is better....
EVERYONE PLEASE POST UR OPINION
thanks in advance:)
 
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i have qtn...is giving AS better or giving the complete A LEVEL is better....
EVERYONE PLEASE POST UR OPINION
thanks in advance:)
Definitely giving AS is better. Even though I don't have the experience but I'm pretty studying for both the courses at the same time is going to be very tough.
 
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i have qtn...is giving AS better or giving the complete A LEVEL is better....
EVERYONE PLEASE POST UR OPINION
thanks in advance:)
It depends from person to person. I had a friend who gave 6 subjects in 6 months and scored 6A*s and a friend who is giving just As level since 2 years and yet he is stuck at D. So now as I said, it depends. If you love studying and your complete focus is in studies and wanna score good u need to practice heck so muchhhhhhhhhhhhhhhhhhhhh!!

For me, I think giving As first then A2 is better option as I cant take both load together.
You can give 2 subjects As and A level in november and other 2 in summer and other 2 in next november.. So in just one year you are done with your A levels with 6 subjects, which is so good if u score more than B in it. This is what I think.

Good luck.. :D
 
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It depends from person to person. I had a friend who gave 6 subjects in 6 months and scored 6A*s and a friend who is giving just As level since 2 years and yet he is stuck at D. So now as I said, it depends. If you love studying and your complete focus is in studies and wanna score good u need to practice heck so muchhhhhhhhhhhhhhhhhhhhh!!

For me, I think giving As first then A2 is better option as I cant take both load together.
You can give 2 subjects As and A level in november and other 2 in summer and other 2 in next november.. So in just one year you are done with your A levels with 6 subjects, which is so good if u score more than B in it. This is what I think.

Good luck.. :D
You're giving 6 subjects?! :confused::whistle:
 
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Crms is proportional to sqrt(T)
Now solve it.
i can't
If I use mean square speed is proportional to T, I get 120 not 1200 :/( which is the answer)
my working is:
<c^2> propotional to T
Since crms is 500 <c^2> must be 500^2 i.e 2500000
So 2500000/300(T) = 8333.3 ( proportionality constant k)
Therefore T2 should be equal to
New <c^2> /k i.e 1000000/8333.3= 120:/
 
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i can't
If I use mean square speed is proportional to T, I get 120 not 1200 :/( which is the answer)
my working is:
<c^2> propotional to T
Since crms is 500 <c^2> must be 500^2 i.e 2500000
So 2500000/300(T) = 8333.3 ( proportionality constant k)
Therefore T2 should be equal to
New <c^2> /k i.e 1000000/8333.3= 120:/
Crms is proportional to sqrt(T)
Crms1/Crms2 = sqrt(T1)/sqrt(T2)
500/1000 = sqrt(300)/sqrt(T2)
T2 = 1200K
 
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