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Physics: Post your doubts here!

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hiii, does anyone have any clue on whats coming in physics paper 31 this may/june? please share, thanks
 
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My Book says :



1.Back Emf seems to imply opposition, something not wanted, yet in a motor it is the induced emf that is responsible for the mechanical work output of the motor.

2.The workdone against the induced emf in a motor is the useful work output of the motor. Workdone against the resistance of the wires is wasted as thermal energy


explain please?

How is back emf responsible for the ouput of a motor? :S isn't motor supposed to provide us force or mechanical energy
 
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the gradient of boyle's law graph represents Temperature or the area under the graph? or neither of them? if we are asked to draw a graph at a higher temp and at a lower temp, why should we draw the graph of higher temp slightly above that for lower temp. I've seen that in several books but fail to understand why
 
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View attachment 60059
can anyone help me with this qtn...???
First consider the left two columns of mercury. The pressure difference between the atmospheric pressure and air inside the colum is given by:
P - 760 = x (we are subtracting 760 from P since we can see that air inside is at a higher pressure than atmospheric pressure)
P = 760 + x ---- (i)

Now consider the right two columns of mercury. The pressure difference b/w the air inside and atmospheric pressure is given by :
P - 760 = 50 - y
P = 810 - y ----(ii)

Solve these two equations (i) & (ii), you'll get,
760 + x = 810 - y
x + y = 50
^ this expression tells us that sum of the values of x & y must be equal to 50, so eliminate all those options which do not sum up to 50. This is will relieve our headache a bit :p Phew! A & D are finally gone :D

Now you know that between B & C, there's one culprit option :p
Substitute the values of x & y from these two options into the equations (i) & (ii). If both the values in an option satisfy both equations, then that will be our required answer.

So put them one by one:

Option B:
780 = 760 +20 (Correct!)
780 = 810 - 30 (Correct!)

Option C:
810 = 760 + 30 (Incorrect!)
810 = 810 - 20 (Again incorrect!)

So the correct option is B.

I hope it makes sense :p
 
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pp.PNG
the gradient of boyle's law graph represents Temperature or the area under the graph? or neither of them? if we are asked to draw a graph at a higher temp and at a lower temp, why should we draw the graph of higher temp slightly above that for lower temp. I've seen that in several books but fail to understand why
Boyle's Law states that for given mass of gas at a constant temperature (oC or K), the product of the pressure multiplied by the volume is a constant

The graph shows how the pressure and volume vary according to Boyles Law at two different temperatures

    • At lower temperatures the volume and pressure values are lower
    • so the gradient of higher temperature T2 is steeper than T1
 
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First consider the left two columns of mercury. The pressure difference between the atmospheric pressure and air inside the colum is given by:
P - 760 = x (we are subtracting 760 from P since we can see that air inside is at a higher pressure than atmospheric pressure)
P = 760 + x ---- (i)

Now consider the right two columns of mercury. The pressure difference b/w the air inside and atmospheric pressure is given by :
P - 760 = 50 - y
P = 810 - y ----(ii)

Solve these two equations (i) & (ii), you'll get,
760 + x = 810 - y
x + y = 50
^ this expression tells us that sum of the values of x & y must be equal to 50, so eliminate all those options which do not sum up to 50. This is will relieve our headache a bit :p Phew! A & D are finally gone :D

Now you know that between B & C, there's one culprit option :p
Substitute the values of x & y from these two options into the equations (i) & (ii). If both the values in an option satisfy both equations, then that will be our required answer.

So put them one by one:

Option B:
780 = 760 +20 (Correct!)
780 = 810 - 30 (Correct!)

Option C:
810 = 760 + 30 (Incorrect!)
810 = 810 - 20 (Again incorrect!)

So the correct option is B.

I hope it makes sense :p
thanks alots......:):)(y)
 
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View attachment 60060

Boyle's Law states that for given mass of gas at a constant temperature (oC or K), the product of the pressure multiplied by the volume is a constant

The graph shows how the pressure and volume vary according to Boyles Law at two different temperatures

    • At lower temperatures the volume and pressure values are lower
    • so the gradient of higher temperature T2 is steeper than T1
so basically the temperature is the product of P and V>?
 
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The question asked us to place a capacitor for smoothing in the circuit
Why should it be across SQ?
eScreenshot 2016-04-02 21.20.27.png
 
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so basically the temperature is the product of P and V>?

actually the product PV is constant at a constant temperature
temperature is not equal to the gradient
it is CONSTANT
as temperature remains constant the same amount of energy given to the system persists throughout its operation and therefore, theoretically, the value of (PV) k will remain constant
however, at a higher constant temperature the product PV will also increase therefore, there is a difference in the gradients
 
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upload_2016-4-6_17-29-15-png.60063

helppppppppppppp
 
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upload_2016-4-6_17-29-15-png.60063

helppppppppppppp
For this use the formula s=ut+1/2at^2
Since the initial velocity is zero so ut can be eliminated and then rearrange to make a the subject which becomes a= 2s/t^2
Now you can see that s and a are directly propotional so an increase in s will result in greater acceleration whereas a and t are inversely propotional. Check all options accordingly. A: If h is smaller, a must be smaller hence incorrect
B: Again h is smaller and t is larger both effects making the a smaller
C: h is larger , yes that increases but then t is also larger which sort of cancels out the effect
D: h is measured correctly while t is small which makes a larger and hence is the correct answer
 
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For this use the formula s=ut+1/2at^2
Since the initial velocity is zero so ut can be eliminated and then rearrange to make a the subject which becomes a= 2s/t^2
Now you can see that s and a are directly propotional so an increase in s will result in greater acceleration whereas a and t are inversely propotional. Check all options accordingly. A: If h is smaller, a must be smaller hence incorrect
B: Again h is smaller and t is larger both effects making the a smaller
C: h is larger , yes that increases but then t is also larger which sort of cancels out the effect
D: h is measured correctly while t is small which makes a larger and hence is the correct answer
thank u
 
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