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In the old syllabuses, there was only one type of Beta decay,which is B- decay . So whenever they mention beta decay we will assume it to be B- .9702_s09_qp 1
Ans is C
im confused there are two types of beta decay
someone please explain the answer
QView attachment 60625
It maybe considered as e.c.f. 'error carried forward' , and you may lose 1-2 marks at maximumYeah so I made a huge blunder in my Physics paper 3 practical exam. Instead of measuring and recording length of x in question 1, I measured it from the opposite side so my readings are kind of 1-x rather than x. This did mess up my trend in graph as well.
Up to how many marks will I lose for the table and the graph because of this?
(Since no one replies in threads, I'll post this here xD)
In order to fly North.. He has got to steer in a way that cancels the effect of wind. So the leftward velocity has got to be 85.0 kmh-1.Can someone please explain these two questions? theyre both D.
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For the second MCQ, just flip the wave and you'll get the answer. Flip it like this:Can someone please explain these two questions? theyre both D.
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View attachment 60628
why do we flip it tho?For the second MCQ, just flip the wave and you'll get the answer. Flip it like this:
View attachment 60629
Your reply really made my day but this is question 1 we are talking about. My trend in graph is opposite and the whole table of results has wrong values of x (other calculations, decimal places, s.f, column titles with there units are perfectly fine though). My Sir said that I may loose upto 5-6 marks for this. Well either way, I'll be trying my best for paper 1. Thanks for replyingIt maybe considered as e.c.f. 'error carried forward' , and you may lose 1-2 marks at maximum
Question 6: Original length is 0.8+0.2 because of systematic error, it appeared less. Uncertainties are added up so 0.02mm + 0.02mm = 0.04 total uncertainity. UC % = 0.04/1.0 * 100 = 4%9702_s15_qp_12.pdf
Can somebody explain question 6. Answer is C
And Question 36. Answer is B
For question 36, the slider is fitted with 3 Ohm resistor so think of it as something as that can move above or below the 3 Ohm resistor but not move as far as to the other resistors.9702_s15_qp_12.pdf
Can somebody explain question 6. Answer is C
And Question 36. Answer is B
My teacher told me that. And he's been teaching since 2005. You won't lose marks in graph. Because you already took your values of x to be opposite of what was required. Hope this suffices your query!Your reply really made my day but this is question 1 we are talking about. My trend in graph is opposite and the whole table of results has wrong values of x (other calculations, decimal places, s.f, column titles with there units are perfectly fine though). My Sir said that I may loose upto 5-6 marks for this. Well either way, I'll be trying my best for paper 1. Thanks for replying
Thanks, that's reassuring.My teacher told me that. And he's been teaching since 2005. You won't lose marks in graph. Because you already took your values of x to be opposite of what was required. Hope this suffices your query!
Where did the 12 come from. Shouldnt it be 9?For question 36, the slider is fitted with 3 Ohm resistor so think of it as something as that can move above or below the 3 Ohm resistor but not move as far as to the other resistors.
The 4 Ohm resistor will have a P.d of 4V across it according to the P.d formula: 4/(4+3+2) * 12
So 5V from total will be left, the 3 Ohm resistor will have P.d 3V across it so 2V will be left from the total. The last 2V will be the P.d across the 2 Ohm resistor. Here's a pic for better understanding. Think of blue lines as far as the slider can go.
Yeah sorry, it is 9V. My bad.Where did the 12 come from. Shouldnt it be 9?
I did it as follows:
Lowest :
(2/2+4+3) * 9 = 2V and
Highest :
(5/2+4+3) * 9 = 5V
Anyways thanks for both the explanations
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