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Physics: Post your doubts here!

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hi bro,
AoA wr wb
u4u9c.jpg

plz explain this solution
from where did u took this question ? is this answer really correct. i learned the formula in the cambrdige book which says in this case => AB/ AC into Eo i.e .65/1 into 12 = 7.8 Volt.

but here i see a different situation where first we divided ab length with total length and then multiplied with the total resistance of the wire. this gave us resistance across AB wire,

then we used this resistance to find the unknown e.m.f. of the test cell is this whole formula correct in the image?
 
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from where did u took this question ? is this answer really correct. i learned the formula in the cambrdige book which says in this case => AB/ AC into Eo i.e .65/1 into 12 = 7.8 Volt.

Well I think your formula only works if there is no other resistance in the circuit ( like the 20 ohms of internal resistance ) ... Since the whole of the line would actually have a P.D. of 12 V so AB/AC into 12... This example is actually somewhere on the site's revision pages. The last one in the D.C. area right here: http://www.xtremepapers.com/revision/a-level/physics/dc_circuits.php

Check my previous reply if you need more details. : )
 
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Can anyone please explain this question from paper 2?

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s11_qp_21.pdf
Q number 5 part B
maximum current will be possible when the voltage across 6 ohm resistor equals to driver cell voltage or when there is least resistance in the circuit. i.e 12, when its 12, I =V/R ,
12/6 = 2 A .
Minimum will be zero . i am not sure bout this but maybe when the jockey is move towards the extreme position then the voltage or resistance might bcm zero then current will be zero as well :/ plz someone else clarify. Thanks
 
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Two solid substances P and Q have atoms of mass MP and MQ respectively. They have NP and NQ atoms per unit volume such that NP= NQ. It is found by experiment that the density of P is greater than that of Q.

Which of the following deductions from this experiment must be correct?

A MP > MQ

B NP > NQ

C MPNP > MQ NQ

D MP/NP = MQ/NQ
A? maybe experimental error which caused wrong mass to be calculate which resulted in difference in densities? caz atoms atoms per unit volume will remain same..share the correct option
 
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Well I think your formula only works if there is no other resistance in the circuit ( like the 20 ohms of internal resistance ) ... Since the whole of the line would actually have a P.D. of 12 V so AB/AC into 12... This example is actually somewhere on the site's revision pages. The last one in the D.C. area right here: http://www.xtremepapers.com/revision/a-level/physics/dc_circuits.php

Check my previous reply if you need more details. : )
ok you think but you are not sure. i can memorize the situation just like in the questions above. Thank You. :)
 
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A? maybe experimental error which caused wrong mass to be calculate which resulted in difference in densities? caz atoms atoms per unit volume will remain same..share the correct option

I don't know the correct answer... It is C in one of the past year papers... But a few words have been added to this question which has changed it I think...
 
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hi bro,
from where did u took this question ? is this answer really correct. i learned the formula in the cambrdige book which says in this case => AB/ AC into Eo i.e .65/1 into 12 = 7.8 Volt.

but here i see a different situation where first we divided ab length with total length and then multiplied with the total resistance of the wire. this gave us resistance across AB wire,

then we used this resistance to find the unknown e.m.f. of the test cell is this whole formula correct in the image?
in the revision section go to dc circuits its the last problem there..
 
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It is called the "Potential Difference across the resistor ". So if 1 end of the resistor has a potential of 3 V and the potential difference is 6.75, then:
3-x= 6.75
x= 3 - 6.75

Concerning the potential divider question:

I'm not entirely sure of this answer but I understand that since the galvanometer is indicating a zero current, therefore the potential difference between the positive plate and B is zero ( same with the negative plate and A ). Why? Because if there was a potential difference there should be a current passing. This does mean that the potential difference across AB is equal to the potential difference across the cell being tested. Thus, you simply need to find the P.D. across AB.

By using ratio of length to resistance, we get the resistance of AB. Then again by using ratio of resistance to P.D. we get the P.D. across AB.

1 ---> 60
0.65 ---> ?

Then

60 + 20 ---> 12
39 ---> ?

Hope this helped. : )
Jazakallah tht helped!!

just one thing why did u add 60+20?
 
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Aoa, Is there any possibility that i might get solved paper 1 of physics in here? year 2002-09. . .There're so many mcqs im confused about :/
 
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