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v^2=u^2+2asView attachment 62384
M/J 2016 (13)
Thanksv^2=u^2+2as
u=8
a=-9.8
s=1.9
therefore v=5.17.....
1/2mv^2=Ek
so 4.014J THE ANSWER IS A
using kirchoff 1st law conservation of charge we can say the current coming out of the cell is 1.2+0.4=1.6AView attachment 62390
O/N 2015 (12)
thnxusing kirchoff 1st law conservation of charge we can say the current coming out of the cell is 1.2+0.4=1.6A
no we find the potential difference of the 80 ohm resistor. v=ir so v=96 since 1.2*80=96v
so terminal potential is also 96v because parallel components have the same potential difference.
using the formula
terminal p.d=EMF*current(internal resistance) or v=E-IR
we get 96=120-1.6r
so r is equal to 15 so the answr is A
I have the same doubt does anyone have a solution?View attachment 62385
O/N 2016 (13)
vertical:View attachment 62385
O/N 2016 (13)
I guess you did it like this 8= ;[ 1/R + 1/2R ]^-1http://papers.gceguide.com/A Levels/Physics (9702)/9702_m16_qp_12.pdf
Q37 anyone and 34..35
q 35 is quite simple
I hope you are aware of this technique of finding Resistance
R = (R1 * R2)/ (R1 + R2)
so it can be done like
8 = (R* 2R)/(R1 + 2R)
straight it out and you get R= 12
Total distance = 200 kmAns is D
O/N/13 V13
The Electric Field is upwards hence the Potential of the upper plate should be lower than the lower plate.Ans is A
9702_13 2016
I'm getting +320 instead of -320The Electric Field is upwards hence the Potential of the upper plate should be lower than the lower plate.
EFS= V/d
60000= - x - 80/4x10^-3
x= -320 (A)
View attachment 62392
2013 ... may...13
Opps I wrote it the opposite way around -80--x / 4x10^-3 = 60 ,000I'm getting +320 instead of -320
x-80/0.004=60000 then x is 320
is it -320+-80 or -320--80?
bcos x-80=240
p.d across 80 ohm resistor ;View attachment 62390
O/N 2015 (12)
This is the hardest question!!! I spent a 5 hours trying to solve this!
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