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omg right thank u so much!!(v^2)-(u^2)=(0)-(1.0^2)= -1.0
2s = 2*3.5*10^-2=0.07
a=1.0/0.07 = -14.2857ms^-2
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omg right thank u so much!!(v^2)-(u^2)=(0)-(1.0^2)= -1.0
2s = 2*3.5*10^-2=0.07
a=1.0/0.07 = -14.2857ms^-2
you are welcome anytimeomg right thank u so much!!
Tysmm for the answerss and Can you explain a bit about how you knew that it will occur lamda/4 and lamda later ?Y1 will occur again 1/4 lamda later and 1 lamda laterView attachment 62372
Tysmm for the answerss and Can you explain a bit about how you knew that it will occur lamda/4 and lamda later ?
I actually do get it now and I realize its so simple . Its just that as we move in the y direction at that very same displacement ....from the rest position (x line). Thankyouu!you want to find out when you will get the same length of amplitude as y1, so in this case Y1 MUST BE POSITIVE, and the same amplitude will thus occur one wavelength later as two points on a single transverse wave with the same phase difference will have the SAME AMPLITUDE (length from the origin line) (look at the second line in my diagram). The first line is 1/4 lambda later as two points 1/4 lamda later will also have the SAME AMPLITUDE (length from the origin line) .
I'm sorry but explaining this is a bit difficult for me, but I hope you get the idea by looking at my drawing. I'm sorry if I couldn't explain it to you.
I actually have to show you the diagram myself and talk to make you understand, maybe a video, but that's not possible! Words can only take you to till a limit!!
hope it helps you
you're welcome anytimeI
I actually do get it now and I realize its so simple . Its just that as we move in the y direction at that very same displacement ....from the rest position (x line). Thankyouu!
The sphere will not move in a diagonal direction so S= Qhelp me with question 325 please....how is upthrust greater than force P ? if upthrust is greater than dowmward force wouldn't the sphere float ? i went for option B ...answer is A
Q34
P = I^2 R 4.0=I^2(20)
Current in circuit = 0.45 A
V=Ir = 0.45*20 = 9.0 V
From kirchhoff's 2 law 16= 9+0.45R R= 16
Q38 View attachment 62370
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