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first,you might want to separate the data.HELPPP.
The pressure at sea level is 100000Pa. The density of sea water is 1030kg/m3. What is the approximate pressure 80m below the surface of sea? Answer is 900000Pa. How
density=1030
h=80
g=9.81
P=dgh=1030*9.81*80=808344
we get the answer 900000 by adding 100000Pa to 808344 which is 908344 which is approximately 900000.this is because the pressure applied 80m below the sea level is not just the waters pressure,but also the atmospheric pressure.
i hope this helps,even though my explanation seems all over the place.