Physics: Post your doubts here!

[omg]

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w11_ms_51.pdf
pls pls pls pls cn i get a diagram fr q.1???

 

[NIM]

i need som small and good notes abut physics....
so blind in Phy...

 

[Rabib_69]

CAN ANYONE EXPLAIN TO ME WHY ORBITS ARE OF IMPORTANCE? (2 marks)

 

[omg]

how to draw a hall probe for the exp design qs???????????????????
PLEASEEEEEEEEEEEEEEEEEEEEEE helpppp any11111111

 

[raamish]

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s11_qp_22.pdf

Qs 1c(i) For this qs i applied the formula s=ut+0.5at2. I put 20 as (u) in the formula to get the answer. But in the marking scheme the u has been taken as 0. Please help.

Qs 5a(iii) I did: P=I2R
2.5*2.5*3.3=20.625. But in the marking scheme the solution and answer are different.

 

[histephenson007]

i need som small and good notes abut physics....
so blind in Phy...

http://www.xtremepapers.com/revision/a-level/physics/

 

[pratikdahal]

no idea about this question ..
please help me with this !!
thank you in advance

 

[hassam]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s03_qp_4.pdf
5 d ii ...cn u tell where ,ark shud be.....shud it ne on the bottom line of square

 

[Zishi]

View attachment 7563 no idea about this question ..
please help me with this !!
thank you in advance

At t=0, the mass of iron will be zero grams. After 2.6 hours, mass of iron will be 0.7 micrograms. At t=5.2 h, mass of iron will be (0.7+0.35) micrograms. When m grams of manganese decays, it produces n grams of iron because both of them have same Ar. Do you get it now?

 

[Zishi]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_4.pdf
5 d ii ...cn u tell where ,ark shud be.....shud it ne on the bottom line of square

Yes, it should be on bottom line of the square. Mark scheme just says that in different words. . .

 

[pratikdahal]

At t=0, the mass of iron will be zero grams. After 2.6 hours, mass of iron will be 0.7 micrograms. At t=5.2 h, mass of iron will be (0.7+0.35) micrograms. When m grams of manganese decays, it produces n grams of iron because both of them have same Ar. Do you get it now?

It was very helpful....!!
furthermore, how can we calculate the time at which the ratio of (mass of iron-56) / (mass of manganese-56 ) is equal to 9.0 ?

 

[Zishi]

It was very helpful....!!
furthermore, how can we calculate the time at which the ratio of (mass of iron-56) / (mass of manganese-56 ) is equal to 9.0 ?

At that time % of manganese is reduced to its 1/10th value to form 9/10 of iron(as 9/10 of manganese is decayed). Then use x = xo(exp)-λt by putting x=1/10 times xo.

 

[pratikdahal]

I

At that time 9/10 of manganese is reduced to its 1/10th value to form 9/10 of iron. Then use x = xo(exp)-λt by putting x=1/10 times xo.

I am sorry, 'cause i don't get how come "9/10 of manganese is reduced to its 1/10th value to form 9/10 of iron"??
can u just elaborate a bit more

 

[Zishi]

I
I am sorry, 'cause i don't get how come "9/10 of manganese is reduced to its 1/10th value to form 9/10 of iron"??
can u just elaborate a bit more

Oh, sorry - my wording went wrong. I've edited the original post.

 

[Sara200]

need help with
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s05_qp_4.pdf
Q7 part (a) how do we make the graph??

 

[Zishi]

need help with
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_4.pdf
Q7 part (a) how do we make the graph??

My, my. Would you bother to see the posts above? The same question is answered in them.

 

[hm12]

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w11_qp_43.pdf

please explain question 11 part b(ii)

 

[raamish]

Please somebdy answer my questions as well

 

[Nikesh]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_22.pdf

Qs 1c(i) For this qs i applied the formula s=ut+0.5at2. I put 20 as (u) in the formula to get the answer. But in the marking scheme the u has been taken as 0. Please help.

Qs 5a(iii) I did: P=I2R
2.5*2.5*3.3=20.625. But in the marking scheme the solution and answer are different.

In Q1, u=0 for vertical component not for horizontal, so there is use of u = 0 in MS

 

[djmohammad]

hell yeah ... i wanna know about viscosity toooo