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Physics: Post your doubts here!

Unicorn

Unicorn

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raamish

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Unicorn said:
honey are you ok? there is still no 4b(iv) :confused:
Click to expand...

yeh honey im ok. the problem here is that even though i changed the ppr from w10 to w11 it was still opening the previous paper. just go to the adressbar and change it to w11
 
Idolfanatic95

Idolfanatic95

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Unicorn said:
for question 2 you have
accn = 2.5 x10^15
time = 2.4 x10^-9
intial speed= 5 x10^7

and u know that the electron is launched halfway between the plates so the distance between it and the plate is 1.5/2 =0.75

using equation of motion= s= ut +(at^2)/2 you get s to be 0.1272 which is much less than 0.75 so no it does not hit it

for question 4 ur diagram is probably wrong draw it again
Click to expand...
I drew again. didn't get anywhere close to 41-48 :s cud u draw it for me?
 
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robotic94

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Unicorn said:
Ok View attachment 10429

as you can see from the diagram I rearranged the forces but didn't change the direction
the angle between T1 and T2 is 90 because T1 is at an angle of 50 to horizontal and T2 at 40 to horizontal
and the angle between 7.5N and t=T1 is 40 because it is vertically downwards so is perpindicular to horizontal

to find T1 and T2 use trignometery

hope it helped
Click to expand...


Yes i got it now :)
Tysm :D
 
Unicorn

Unicorn

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robotic94 said:
Jeez
i am so sorrry!
q2 it is!
Click to expand...

ok so using the equation v^2=u^2 +2as

for intial state (v would be zero and zero squared is zero so i will leave it out to make it easier to calculate)
so distance will be -u^2/2a =s

for half speed u= 0.5u therefore -> -(0.5u)^2/2a =s' (s' is the unknown distance)
simplyfy equation u get -1/4 *u^2 which is basically -u^2/4/2a which gives -u^2/8a =s'

when ever you have a situation like the above divide the thing you are trying to find by original
ie s'/s = (-u^2/2a) /(-u^2/8a) which gives s'/s =2/8 so s'= 0.25 s

hope it helped
 
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