Physics: Post your doubts here!

[USMAN Sheikh]

whch paper ?

 

[hendrixgirl]

whch paper ?

october/november 2007 paper 4

 

[rz123]

how do you find the are under the curves?
like in oct 07 question 5)b)ii)
where you have to find the charge?
i do not know how to find it. please help me out :s

can u plz attach the link?
the shape which the area under the graph makes has to used in order to find the quantity.

 

[hendrixgirl]

http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w07_qp_4.pdf
question number 5 on this

 

[d_2246]

Hi.. pls can some1 clear these queries of mine:
1- june 2009 paper 4 question 9 part b... i dont seem to get why the radioactive source must decay by 8 % as said in marking scheme

2- nov 2010 paper 43 q 3 part b... why does the position be 2 cm above AB.. and in part iii why do we have to use 2cm as instantaneous displacement of piston..

Thanks in advance!

 

[cats_books_animes]

anyone have any ideas on how to solve question 3 part b from physics (9702) october/november 2010?

 

[hendrixgirl]

i need help in october 2007 paper 4 : http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w07_qp_4.pdf

question 5 , how do you find the area under the graph

and 6 . the last part of the question, how do you know what B is?

 

[tom ed]

http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s09_qp_2.pdf

first variant question no 7 b part 3.....????

 

[TheDealer]

http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s08_qp_2.pdf
Q2 b) ii) HOW?

 

[omg]

http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w03_qp_2.pdf
Q1 PART (c)
pls smby explain it to meeeee

 

[Muhammad Talha]

hi, this is my try:-

2) in this mcq you are given with the angle and horizontal component.use it to find the vertical comp.
Tan30 = Perpendicular / 20 , it comes 11.5N i.e C.

13) no convincing ans but the weight is making a torque of 180 Nm, how? 900 N into .20m (.20 is the perpendicular distance or the radius of the disc)
same torque will be shifted upwards in order to lift this weight i.e 180 = F into 1.20 m it comes 150 N hence B. ( i dnt knw why i took .20 as the perp distance to find the torque created by weight)

14) Power = F v , so k = P over v^3 because you need to add another v in the denominator as F = Power over velocity.

15) what i get is dat if u c in both vessels the height will decrease by half from the original height in the vessel X, means h will bcm h/4 altogether, so the answer will be B mgh/4.

18) pressure = pgh , p ang remain constant. u know that h has increased in the right side of manometer. i.e pressure has increased. there is only option D 2pgh which supports this idea. other three options shows decrease or no change in the pressure.

20) extension directly proportional to length and inversely proportional to area. length is twice so this increase the extension by 2, area has decreased as well by half so this also doubles the extension, total extension raised by 4 times. the ratio of the tension will be 4 /1. (not so clear i know)

21) strain energy = 1/2 F into x so 1/2 into 17 into 30 /100 it comes around 2.5 J but the best estimate would be less then that i.e 2 Joules which is nearest to the whole number. 3J would be very higher i.e A option

25)i dnt understand , it shud be C but its A, d sin Q = n lambda , this s what comes after moving here nd dre things
n/N = sin Q / Lambda

33) U must see that the two cells are not in one direction, cancelling each others voltage. i.e subtract these two 3V- 1.2 V = 1.8 Volt , now use this to find the current in loop 1 which has 9 ohm resistor. I = 1.8 / 9 = .20 Ampere i.e B.

Thank you so much.....

 

[hassam]

Assalamu alaikum,
I expect you have also done the first part of this question. You get E=deltaV/delta r or E= V/r or in other words, E is the gradient of V and r graph.
You can also sketch a graph on a rough paper , and as a rough work in exam which you can erase afterwards, by taking several values of r, or x which is the same thing in this case. The graph appears to be somewhat like this.(uploaded in the picture).
You get the idea of how the graph is sketched. The graph of E against r is steeper than the graph V against r axis. In the question, you draw a graph which is steeper and a little more downwards than the V against x graph.
Note: In the graph or E against r axis and V against r axis, in the uploaded picture, value of k comes out to be one.
You might find it better to confirm this answer. I don't pretend to be an expert on graphs though.

brother i assked for QUESTION 6 part b TRANFORMER WALE K GRAPHS

 

[NokiaN95638]

http://www.xtremepapers.com/CIE/ind... Level/9702 - Physics/&file=9702_s09_qp_1.pdf Q no 29
http://www.xtremepapers.com/CIE/ind...Level/9702 - Physics/&file=9702_w10_qp_12.pdf Q no 15, 34
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w08_qp_1.pdf Q no 34
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s10_qp_11.pdf Q no 27, 29
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w09_qp_11.pdf Q no 12,14,15,27,29,32

Please help me with these questions.
Thanks mate

 

[Mustehssun Iqbal]

brother i assked for QUESTION 6 part b TRANFORMER WALE K GRAPHS

oh q:

 

[hassam]

ans bhi kar do

 

[zain786]

guyz can somebody post the answers to this attachment qs plz plz
ther topical mcqs...attachment or post or anything plz

or if not can u guyz plz plz at least post the option answers of the following Qs

for Physical quantities...ans of Qs 4, 6, 11,13, 23, 25, 27, 32, 33, 47


and for States of Matter ans for Qs 13, 17, 19, 27
thanx for reading...

 

[XPFMember]

Thank you so much.....

Q:25 dsinx = ny
Sinx/ny = n/d
d= 1/N
so we get Nn hence ans is A

 

[XPFMember]

Assalamoalaikum wr wb!
I need help with Q:4c of Nov:2007 Paper:2
I don’t understand the last step…
Mark scheme

 

[confused123]

http://www.xtremepapers.com/CIE/index.php?dir=International A And AS Level/9702 - Physics/&file=9702_s09_qp_1.pdf Q no 29
http://www.xtremepapers.com/CIE/index.php?dir=International A And AS Level/9702 - Physics/&file=9702_w10_qp_12.pdf Q no 15, 34
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w08_qp_1.pdf Q no 34
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s10_qp_11.pdf Q no 27, 29
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w09_qp_11.pdf Q no 12,14,15,27,29,32

Please help me with these questions.
Thanks mate

oct/nov 2010: 34, the resistance is increasing as we move on so the graph will go steeper and steeper with the distance. B supports this idea.

 

[confused123]

http://www.xtremepapers.com/CIE/index.php?dir=International A And AS Level/9702 - Physics/&file=9702_s09_qp_1.pdf Q no 29
http://www.xtremepapers.com/CIE/index.php?dir=International A And AS Level/9702 - Physics/&file=9702_w10_qp_12.pdf Q no 15, 34
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w08_qp_1.pdf Q no 34
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s10_qp_11.pdf Q no 27, 29
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w09_qp_11.pdf Q no 12,14,15,27,29,32

Please help me with these questions.
Thanks mate

oct/nov 2008 : the total current which the battery can supply is I = Q/t , so 100,000 by 2 = 50,000A , this is the max current battery can hold after it stops charging.
one start requires 200A

total number of starts = 50,000 / 200 = 250