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Physics: Post your doubts here!

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june 06) q2: we have to remember the reasonable estimates. option D is correct cox the wavelength of visible light is in nanometres.
12) momentum before and after remains same. before collision it was:
3mv - 2mv
= mv
before = after
mv = 4mv'
where v' is the new speed
m cancels out
v' = v/4
14) turning effect = F.d costheta
for a larger turning effect, F and d should be larger and "cos theta" must be greater
cos theta increases as angle decreases.
so option B is correct

can the turning effect of force also be equal to F.d sintheta in other situations or is it always F.d costheta?
 
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nov 08 q27) it is a stationary wave. so there is half wave between 2 maximum. half wave is 15mm so full wave will be 30mm. v = f*lambda
3*10^8 = f * 30*10^-3
f = 1*10^10
option C

Isnt the distance between the two maxima equal to one wavelenght not half?
 
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can the turning effect of force also be equal to F.d sintheta in other situations or is it always F.d costheta?
it can be F.d sintheta. but the distance taken should always be perpendicular to the pivot. in this ques perp distance will be cos theta
 
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Isnt the distance between the two maxima equal to one wavelenght not half?
for a stationary wave, it is half wavelength. cox we need antinode at one end and node at other. first time it will be quarter wavelength. next time it will be 3/4 wavelength. so difference between the two will be half wavelength
 
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u r asking same questions again and again. i have already answered these. type the confusion in the respective mcq.

18th : Power = F into V , F = ma , so m1g-m2g will give you the tension in the string. multiply it with v, u will get the power. D is the right option.

19) Pressure = p g h , 1020 into 10 into 10,000m = 102000000 = 10^8 Pa D option!

i don't know 24!

don't know 33

34: done on previous pages here
 
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27) its zero because the distance moved by the unit positive charge is not in the direction of the force applied. the force here is towards the centre. centripetal force. what say?

29)direction of field is INTO the paper. u need to make 3D view in your mind. its coming out of the paper from positive to negative. when electron beam travels from left to right, it will come out of the paper into the observer eyes.
 
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27) its zero because the distance moved by the unit positive charge is not in the direction of the force applied. the force here is towards the centre. centripetal force. what say?

29)direction of field is INTO the paper. u need to make 3D view in your mind. its coming out of the paper from positive to negative. when electron beam travels from left to right, it will come out of the paper into the observer eyes.

Thnks Mate.
 
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