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this is very easy if you were able to do part a , in part a you re asked to calculate the gradient!Please explain this to me.
9702/02/M/J/04
(Paper 2 - M/J 04)
Question 3 - Part b) ii)
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_qp_2.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s04_ms_2.pdf
Thanks in advance.
you found the gradient =s/t^2 . think of this kinematic equation s=0.5 at^2 . we do not consider s= ut+0.5 a^2 because the car does not have any constant initial velocity before its acceleration .
now to calculate acceleration , a= 2 x s/t^2 that is 2 x the gradient you found . ( i am taking s as the distance here)