Physics: Post your doubts here!

[deep mehta]

what will be the current time graph and voltage time graph after an ac current passes through a diode???? PLZ Reply fast I M really stuck on this question

 

[geek101]

emkay here ya go...

 

[emkay]

emkay here ya go...

variant 21 of 2012 please? you accidentally posted 2010

 

[geek101]

variant 21 of 2012 please? you accidentally posted 2010

oops sorry

 

[queen of the legend]

people how was the exam today ?!?

 

[bamteck]

people how was the exam today ?!?

Not bad ! 50-50

 

[InnocentAngel]

Mone sonner zordi !
I was like today

 

[queen of the legend]

No more discussions going on !!!! seems that everyone attended the oct exam !.................well then good luck with the results

 

[bamteck]

No more discussions going on !!!! seems that everyone attended the oct exam !.................well then good luck with the results

oO'

 

[emkay]

its sad how this hip and happening thread has once again gone back to the era of darkness.

 

[alcoholic 111]

Paper 22 is being discussed in other threads please check

 

[MysteRyGiRl]

dis is da A2 thread ryt? :S

 

[alcoholic 111]

dis is da A2 thread ryt? :S

Not specifically you can discuss any sort of problem here both AS and A'level

 

[MysteRyGiRl]

^ oki

 

[AhShun]

Mone sonner zordi !
I was like today

LOL ti cool
But it was a nice paper(apart from some silly mistakes)

 

[issac0215]

Hi , can someone please briefly explain how to determine the maximum pd that can be safely be applied across the capacitor?

 

[Silent Hunter]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s03_qp_1.pdf

Q3,5,20??

thank you

 

[alcoholic 111]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_1.pdf

Q3,5,20??

thank you

3) resolve the left 10 N force into it's component
vertical = 10sin60 = 8.66N
horizontal= 10cos60 = 5 N

Now consider the horizontal forces
find the result of the horizontal forces , since they are in opposite direction we would subtract them
10 - 5 = 5 N

So NOW
we have vertical and horizontal forces so find the overall resultant
R = √ (5)² + (8.66)²
R = 10 N

 

[alcoholic 111]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_1.pdf

Q3,5,20??

thank you

5)
error is ±3 % So
3/100 x 327.66 =9.8298

So this means that the True/exact value of speed is either ±9.8298 above or below 327.66
So 330 ms^-1

 

[alcoholic 111]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_1.pdf

Q3,5,20??

thank you

20)

pressure is lowered by 10% So

10 /100 x Po = po /10

So

po/10 = density x g x L

rearranging we get

L= Po /10 density x g