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can anyone please help its the part b that i need help in
Your informations seems perfect but I guess you messed the formula up! If its E=1/2 mv^2 then should V=√2E(divided by)M. Because M is multiplying with V and would go and divide there?Velocity at launch
E=1/2 mv^2
v=√2Em
horizontal component of velocity at launch (u)
cos60=u/√2Em
u=0.5√2Em
at the highest point, the object has no vertical velocity, but has the same horizontal velocity it had at launch (if we ignore air resistance, horizontal velocity does not vary through the flight since there are no horizontal forces acting on the projectile)
so
vertical component=0 horizontal component=0.5√2Em
now since we have both the components of velocity at the highest point we ll calculate the resultant velocity using pythagoras theorom which is going to be the same as the horizontal component of velocity
using this resultant velocity we ll calculate the K.E at the highest point
K.E=1/2 mv^2
K.E=1/2 m(0.5√2Em)^2
K.E=0.25E (answer)
hope i was able to help
yes i guess i made a little mistake there,i mistakenly multilpied m rather than dividing itYour informations seems perfect but I guess you messed the formula up! If its E=1/2 mv^2 then should V=√2E(divided by)M. Because M is multiplying with V and would go and divide there?
can u please point out my mistake pleaseYour informations seems perfect but I guess you messed the formula up! If its E=1/2 mv^2 then should V=√2E(divided by)M. Because M is multiplying with V and would go and divide there?
can u please point out my mistake please
help people
as water is going to expand on evaporating soHi friends I seriously need help for the question below It's june 2007 paper 2 number 3 c (ii)
View attachment 21237
PLEASE HELP DEAR FRIENDS
this is from which past paper??To make a potentiometer, a driver cell of 4.0 V is connected across a 1.00 m length of resistance wire.
a. a) What is the potential difference across 1 cm length of wire? What length of wire has p.d. of 1.0 V across it?
b. b) A cell of unknown e.m.f E is connected to the potentiometer and the balance point is found at a distance of 37.0 cm from the end of the wire to which the galvanometer is connected. Estimate the value of E. Explain why this can only be an estimate.
c. c) A standard cell of e.m.f 1.230 V gives a balance length of 31.2 cm Use this value to obtain a more accurate value for E.
I is prop to amp^2A beam of red light has twice the intensity of another beam of the same colour. Calculate the ratio of the amplitude of the waves.
I need help with the following question ASAP
The density of a material of rectangular block was dteremined by measuring the mass and the linear dimensions of the block. Below are the results obtained with their uncertainities
m=25+/-0.1g
l=5.00+/-0.01cm
b=2.00+/-0.01cm
h=1.00+/-0.01
The density was calculated to be 2.5gcm^-3. What was the uncertainity with this result?
thanxdensity = mass/vol
volume = l x b x h
Δv/v = Δl/l + Δb/b + Δh/h
Δv/v = 0.01/5 + 0.01/2 + 0.01/1
Δv/v = 17/1000
Δp/p = Δm/m + Δv/v
Δp/2.5 = 0.1/25 + 17/1000
Δp = 0.05
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