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velocity of all the electromagentic waves is the same i.e 3*10^8
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Q14How do we solve questions 14, 19 and 20 in this paper:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf
Answer to ur first question is 20N using F*t=pI need urgent help in these questions below:
1) calculate the force needed to change the momentum of an object from 50 kgms-1 to 250 kgms-1 in 10 sec
2)Winter 2005 , paper 2 , question #4( I need Full explanation because I can't understand anything from the marking scheme )
3) winter 2002 , paper 2 , question #3 ( I need Full explanation because I can't understand anything from the marking scheme )
distance between one minima to the other is 0.5 wavelength
0.5 wavelength=15*10^-3
wavelength =0.03m
we speed of the light is 3*10^8
frequency= velocity/wavelength
3*10^8/0.03 = we get 1*10^10
1*10^3 is kil0
1*10^6 is mega
1*10^9 is gega
so it is 10GHZ
in waveform p there are four crests and so there are four waves ok? (for the motion from 0 to 18)How about this one?
Question 26.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w11_qp_12.pdf
At time t = 0 the waves are in phase. At the dotted line, t = 18s.
At which time is the phase difference between the two oscillations ⅛ of a cycle?
A 4.0s B 4.5s C 8.0s D 9.0s
Answer is B
now to find the phase difference draw two vertical lines from one wave form to the other remember it should be perpendicular to the x axisHow about this one?
Question 26.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w11_qp_12.pdf
At time t = 0 the waves are in phase. At the dotted line, t = 18s.
At which time is the phase difference between the two oscillations ⅛ of a cycle?
A 4.0s B 4.5s C 8.0s D 9.0s
Answer is B
Cheers mate! I owe you oneQ14
power=F*d/t
=F*v
substitute the value of F=kv^2 into the formula above
power(P)=kv^2*v
P =kv^3
k=P/v^3 (answer)
no problemCheers mate! I owe you one
5b(i)first find the capacitance across the parallel combination of capacitors that is C+C=30+30=60pls help me with question 5(b)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_42.pdf
thnx5b(i)first find the capacitance across the parallel combination of capacitors that is C+C=30+30=60
now using the capacitance above find the capacitance across the series combination that is 1/C+1/C=1/30+1/60
total capacitance=20
b(ii)voltage across each capacitor is 6V
find the voltage across the parallel combination that is 1/V+1/V =1/6+1/6=3V
now using the above voltage find the voltage across the series combination that is V+V=3+6
total voltage =9V
Herecan anyone give me the link for oct/nov 2012 pastpapers for bio, chem & phy......thnx
npthnx
Okay i got what you're saying. Guess will have to learn phase differences of 1/8th n 1/4th n all as well cuz I can't recognize it. Btw I dont think there's 0 phase difference at 4s either. There is some...now to find the phase difference draw two vertical lines from one wave form to the other remember it should be perpendicular to the x axis
4s means one wave of waveform Q
4.5 means one wave of waveformP
9s means two waves of waveform Q draw the lines and see what u get
at 4 s u will see 0 phase difference
at 4.5 s there is a difference of 1/8 of a wave
at 9 s there is a difference of 1/4 of wave
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