• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Physics: Post your doubts here!

goodluckayesha

goodluckayesha

Messages
253
Reaction score
1,195
Points
153
syed1995 said:
Yea.. you need to give the refrence.. that since F is directly proportional to extension .. the extension will be same... F=kx where k is constant... I just solved the question .. that depends on the marks of the question ...
Click to expand...
it was for 3 marks hmm I got it :)
thnq so much.....
 
Ariel Robert

Ariel Robert

Messages
84
Reaction score
34
Points
18
Warrior66 said:
i think the answer's D?? (obviously you need to write the actual answer as well in order for me to know if i have got it right and only then would it make sense that i explain how i got it..)
Click to expand...

Bro, The full question is wrong or one of the options are missing...
 
gary221

gary221

Messages
6,440
Reaction score
31,077
Points
698
Sapphires said:
I need help with Questions 4b and 4d, plz. Thank you.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_41.pdf
Click to expand...

4b i) field strength is (negative of) potential gradient (see coursebk, pg 349)
ii) Field strength is proportional to force on Q --> as E = F/q
potential gradient proportional to gradient of (potential energy) graph ---> as potential = potential energy/mass
So, since field strength is (negative of) potential gradient
It implies that filed strength is also proportional to gradient of the graph.

Hope u gt it!!
:)
 
gary221

gary221

Messages
6,440
Reaction score
31,077
Points
698
4 d i) As v can see in the graph, when distance x increases, potential energy bcoms more positive ie potential energy also increases.
This implies that work is done in separating the charges ----> ie the 2 charges r actually attracting each other ---> so they both r oppositely charged!

ii) Doubling the charge on P will mean more work will need to be done to separate the 2 charges ie potential energy will also double.
So, the graph will be steeper n the gradient will increase..

Sapphires...Hope u gt it!
 
Sapphires

Sapphires

Messages
13
Reaction score
5
Points
3
gary221 said:
4 d i) As v can see in the graph, when distance x increases, potential energy bcoms more positive ie potential energy also increases.
This implies that work is done in separating the charges ----> ie the 2 charges r actually attracting each other ---> so they both r oppositely charged!

ii) Doubling the charge on P will mean more work will need to be done to separate the 2 charges ie potential energy will also double.
So, the graph will be steeper n the gradient will increase..

Sapphires...Hope u gt it!
Click to expand...
Thank you! This helped so much!
:)
 
ruler_of_the_world

ruler_of_the_world

Messages
60
Reaction score
92
Points
28
think abt it this way. As u increase the width u let in more light thus at the point previously where u had constructive interference, over there now more waves will coincide due to the widening of the gaps. Thus the brightness increase.
 
gary221

gary221

Messages
6,440
Reaction score
31,077
Points
698
minie23 said:
6(d)
Click to expand...

when m is 1st released, the strain energy in the spring (or the elastic potential energy) is converted to kinetic energy(so results in movement of M) + potential energy due 2 gravity, as M is pulled down due to gravity.
then it reaches S, stretching is max, after which the extension reduces ---> pulling up M again ie height increases.

Hope u gt it!
 
mostafa sedky

mostafa sedky

Messages
1
Reaction score
0
Points
1
Can you plz plz help me urgently how to solve Question 5 paper 21 June 2009 I can't understand it !!!! Physics AS
 
You must log in or register to reply here.
Top