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Physics: Post your doubts here!

sma786

sma786

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Tanvir Azad said:
In question no. 5, fractional uncertainty is being asked.... so:
as speed = distance traveled / time taken
here, distance traveled is 385 - 115 = 270, and its uncertainty is, 1+1= 2mm (its not 1mm bcoz we have to take the uncertainties of both the initial and final values of distance travelled)
again for time taken, 3.5 - 1.5 = 2.0 and its uncertainty is .02 + .02 =0.04mm (same reason as above)
hence, there fractional uncertainties should be, 2/270 + 0.04/2.00
So the key is A.

Hope it helped... :)
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Thankyou very very much :LOL:
 
TaffsAsLevel

TaffsAsLevel

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sara kamal said:
here u have to assume a value of p.d=eg:6 V
so current in circuit =power/voltage=2 amp
nw voltage across P would be 4V and across Q and R would be 2V since they are in parallel
see hw itS 2V(ASSUMING EACH RESISTANCE TO BE 3,SO TOTAL R OF RESISTORS IN PARALLEL=1.5 OHM
NW THERE SHARE OFBATTERYS VOLTAGE=1.5/4.5(TOTAL R) x 6=2V)
anyway nw,
nw since P=VI
power in P=2 x 1(since divided between Q and R=2W

hope u got it,i tried my best
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It's ok I found it out already, thank you for the effort just ask me if you have doubt
 
TaffsAsLevel

TaffsAsLevel

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Y

Yousif Mukkhtar

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sma786

sma786

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Yousif Mukkhtar said:
Q10: {INITIAL=mu) [FINAL= -mu ( because it moving in opposite direction)]
Change in momentum = Final momentum-Initial Moment
=-mu-mu
=-2mu

Q13
Anticlockwise moments= Clockwise moments
20 x 9.81 x60= 100x 10x 9.81 + 50x9.81 x
11772-9810=50x9.81x
x=4 cm clockwise
40+4=44 cm
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Thanks ! :)
 
M

Monojit Saha

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Yousif Mukkhtar said:
Can some one explain these please q12
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_11.pdf

Q20
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w12_qp_11.pdf
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12: Its more of a mechanics question.. First find the acceleration from the two equations. . i- T-800= 8a and
ii) 1200-0T=1200a .. u get a= 2ms-2.. we kno that for a pulley,, the two components travels the same distance and with teh same speed.. so the two bodies will meet half way between 18 m, thus 9 m. So, use v2=u2+2as for anonw of the bodies. taking the s as 9 .. u get the v as 6 ms-1.

20: its simple.. just find the K E developed i.e 1/2 mv2
 
Usman04

Usman04

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hi guys i have many problems to discuss i am writing all the problems below

firsly i have seen many mcqs about how many maximas minimas or bright fringes or observed in differaction grating and number of line per mm is D or N. i remeber one mcq in past paper plzz solve it oct/nov 2012 paper 12 que 30

second problem mcqs 13 from oct/2012
oct/nov 2011 paper variant 12 q26,31 why c is not write in q 31
oct/nov 2011 variant 11 q20 may june 2011 varient 11 q 27
 
Nab900

Nab900

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Assalam O Alaikum,
Can someone please explain q 36 of s12_qp_13
Why is the answer C :confused:
Why isnt the answer D
and q 6 of w12_qp_11
please explain these two questions as deeply as you can





Thanks in advance :D
 
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