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my pleasureBig thanks to 1357911 thoughtblocker and mehria!
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my pleasureBig thanks to 1357911 thoughtblocker and mehria!
9 (B) change in momentum = m v1 -m v2 = 0.1 x 20 - 0.1 x 9 (-30) (since direction opposite velocity sign changes into -ve for 30 m/s)= 5Physics questions - http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf
9,10,13,14,18,19,20,22,24,25,27,29,32,33,35,37,39
The vertical components of both H and W are cancelled by the upwards vertical component of T. Furthermore, T balances out the horizontal component of H too. Thus T has to be the largest of the three. C is the only option.http://maxpapers.com/syllabus-materials/physics-9702-a-level/attachment/9702_s13_qp_11/
Can someone please explain for me how to solve question 16 as soon as possible?
You mean vertical component of H and W are cancelled by upwards vertical componenet of TThe vertical components of both H and T are cancelled by the upwards vertical component of T. Furthermore, T balances out the horizontal component of H too. Thus T has to be the largest of the three. C is the only option.
Yup, sorry that was a typo. Thanks for pointing that out, I've edited itYou mean vertical component of H and W are cancelled by upwards vertical componenet of T
Yo sundeep thanks so much, understood everything except Q14, q29(why is it 2Ee and not Ee)9 (B) change in momentum = m v1 -m v2 = 0.1 x 20 - 0.1 x 9 (-30) (since direction opposite velocity sign changes into -ve for 30 m/s)= 5
In 14 we know that power = force x velocity. Change the question so you get the equation with k on one side and other quantities on other side now substitute force = power/velocity in the new equation to get the answer clear??Yo sundeep thanks so much, understood everything except Q14, q29(why is it 2Ee and not Ee)
For q33 .. i get how you got 0.3 A but dont understand next part, can you explain again? or thorougly
Someone help with this please ^
well it can be dangerous for a human being pulsed gives short bursts of ultrasound energy this is relatively safer than a continuous.Hello! Can anyone make it clear to me why ultrasound is pulsed and not continuous in ultrasound scan??
http://boson.physics.sc.edu/~hoskins/Demos/CathodeRay.htmlHey does anyone have notes on 'CRO', I need them badly?
Thansk a lot Sudeep.In 14 we know that power = force x velocity. Change the question so you get the equation with k on one side and other quantities on other side now substitute force = power/velocity in the new equation to get the answer clear??
In 29 K.E = 1/2 x m x v^2 and Force = eE. Substitute these in the equation displacement = workdone/force. You get x = ((mv^2)/2)/eE
Hence, x = (mv^2)/2eE . The 2 comes from the equation for K.E
In 33 we can divide the equations with ∝ to remove it.
Eg: Suppose you have I1 ∝ S1 and I2 ∝ S2 then I1=k(constant) x S1 and I2 = k(constant) x S2. Now divide these two new equations you can cancel out k(constant) as they are same in both. Then looking back at 33 i just skipped supposing a constant and directly divided first equation by the second one and note I is inversely proportional with R so take care while dividing and obtain I2 in terms of I1 and use kirchoff's first law. That is sum of current entering a junction is equal to the sum of currents leaving it. I hope it's clear and by the way my name is Sudeep not sundeep
a i) (1/100)* +/- 2.05 = +/- 0.02Someone please solve "Q1 (a)(i)(ii) ", link: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_23.pdf
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