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Physics: Post your doubts here!

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Arre Baapre, kya kiya maine?! :D

Hadi, what I drew on that image isn't gradient. I know that much :LOL:

Any point A, B, C or D, we can write as (V, I). The resistance is V/I, which is 1/(I/V).

I/V just happens to be the gradient of the line joining A,B,C or D to the origin ([I-0]/[V-0]). So to show as a diagram, to give geometrical representation, I drew the diagram. Sorry for any confusion.;)
 
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Arre Baapre, kya kiya maine?! :D

Hadi, what I drew on that image isn't gradient. I know that much :LOL:

Any point A, B, C or D, we can write as (V, I). The resistance is V/I, which is 1/(I/V).

I/V just happens to be the gradient of the line joining A,B,C or D to the origin ([I-0]/[V-0]). So to show as a diagram, to give geometrical representation, I drew the diagram. Sorry for any confusion.;)
Are bhai mene usko wahi shamjhaya ._.
 
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If yes :
using POCM( principle.....con momentum)

initial p = final p

initial p of system = 0

final p must also be = o

mass of parent nucleus = Ay( where y is the unified atomic mass constant)

mass of proton = y

mass of daughter nucleus = (A-1)y

o = vy + (A-1)( y )(-u) ( -u cuz u and v are in opposite directions)

rearrange and u`ll end up with v=(A-1)u

P.S. u can ignore y as it`ll cancel out eventually

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Here is work if you dont understand here is direct solution :¬
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mn=(A−1)amump=1amu

pi=pf

0=mnu−mpv

0=((A−1)amu )u−(1 amu) v

(1 amu) v=((A−1)amu)u

v=(A−1)u
 
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The question states that "X is measured with a percentage uncertainty of ±1 % of its value at all temperatures." meaning that the percentage uncertainty is unchanged, so A and B is eliminated.
then you need to apply some logic here, will the actual uncertainty get bigger as you approach 100 or 0?.
you can quickly do some math here, 100x1% = ±1 uncertainty while 0x1% = 0
so answer is C, least actual uncertainty when temperature close to 0
 
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