Isnt there anything regarding it in the examiners repory?
-
We need your support!
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Physics: Post your doubts here!
- Thread starter XPFMember
- Start date
- Messages
- 620
- Reaction score
- 9,085
- Points
- 503
They talk abput 1.6x10^-19 as the highest common factor
- Messages
- 620
- Reaction score
- 9,085
- Points
- 503
Energy is potential into charge
Potential is energy/charge
Gradient of potential=energy gradient/charge
- Messages
- 1,983
- Reaction score
- 3,044
- Points
- 273
from the data the difference between two smallest values is this. and all numbers are multiple of this.
Aren't energy gradient and potential gradient the same thing?
- Messages
- 515
- Reaction score
- 1,447
- Points
- 153
ths is because we r talkng abt the torque... n the formula for the torque= force x (horizontal distance between the forces)
that's y we use the alue of BC cuz it is the horizontal distance between the torques produced in AB and CD
- Messages
- 620
- Reaction score
- 9,085
- Points
- 503
No energy gradient here is Up/r and potential gradient is V/r
- Messages
- 5,330
- Reaction score
- 11,839
- Points
- 698
Exact function of a modulator!?
2- in electric fields
Va+Vb=0
Applied in what cases
2- in electric fields
Va+Vb=0
Applied in what cases
- Messages
- 11
- Reaction score
- 5
- Points
- 13
Light of wavelength 600 nm is incident on a pair of slits. Fringes with a spacing of 4.0 mm are formed on a screen.
What will be the fringe spacing when the wavelength of the light is changed to 400 nm and the separation of the slits is doubled?
A) 1.3mm
B) 3.0mm
C) 5.3mm
D) 12mm
What will be the fringe spacing when the wavelength of the light is changed to 400 nm and the separation of the slits is doubled?
A) 1.3mm
B) 3.0mm
C) 5.3mm
D) 12mm
- Messages
- 11
- Reaction score
- 5
- Points
- 13
need help in solving this...
- Messages
- 620
- Reaction score
- 9,085
- Points
- 503
Brother, The answer to Q37b) is wrongly stated.
The reasons being:
Greater bandwidth
Less attenuation
Less noise
in the coaxial cable
- Messages
- 124
- Reaction score
- 343
- Points
- 73
thank you!!!
- Messages
- 26
- Reaction score
- 21
- Points
- 13
- Messages
- 1,318
- Reaction score
- 1,374
- Points
- 173
For practicals , the last question has calculating k value and then it asks whether the suggested relationship is correct?
What do you write for that?
Like some say that it is correct if the percentage difference is less than the percentage uncertainty calculated in the measurement
But then how exactly to frame your answer?
And also how to frame it when the relationship is not held true (i.e the percentage difference is more than the percentage uncertainty calculated in the measurement)?
What do you write for that?
Like some say that it is correct if the percentage difference is less than the percentage uncertainty calculated in the measurement
But then how exactly to frame your answer?
And also how to frame it when the relationship is not held true (i.e the percentage difference is more than the percentage uncertainty calculated in the measurement)?
- Messages
- 155
- Reaction score
- 27
- Points
- 28
Hi guys! So I have my practical exam tomorrow, does anyone have last minute tips that would be helpful?
Also, do we need to know how to measure using a vernier caliper and micrometer?
Also, do we need to know how to measure using a vernier caliper and micrometer?
ty so muchhhh sir
- Messages
- 2,738
- Reaction score
- 6,309
- Points
- 523
Yes you need to know that.
- Messages
- 2,738
- Reaction score
- 6,309
- Points
- 523
Is the answer A?