Physics: Post your doubts here!

[amina1300]

View attachment 62947
Need help..

V in km/h * 1000m/km * 1h/3600s = V/3.6 in m/s
(1 / 3.6)² ≈ (1 / 13.0) ≈ 0.0772

so, A is the answer.

 

[MShaheerUddin]

explained at
http://physics-ref.blogspot.com/2018/01/when-constant-braking-force-is-applied.html

 

[MShaheerUddin]

http://physics-ref.blogspot.com/2018/01/a-digital-caliper-is-used-to-measure.html

 

[Cutilixious Alizeh]

View attachment 62962

is the ans B?

 

[Cutilixious Alizeh]

View attachment 62953

C?

 

[Cutilixious Alizeh]

View attachment 62947
Need help..

B

 

[MShaheerUddin]

B

Everybody knows that answer is B as it is clearly stated in Marking Scheme
But explanation is what i require

 

[Hamnah Zahoor]

Everybody knows that answer is B as it is clearly stated in Marking Scheme
But explanation is what i require

For finding total displacement we subtract the area under graph that is area of the graph above the x axis minus area of graph below the x axis.

(0.5*1*10)-(0.5*0.5*5)=3.75

 

[MShaheerUddin]

 

[MShaheerUddin]

 

[Laiba inayat]

June 2004
P1 Mcq no. 6 and 7

 

[MShaheerUddin]

June 2004
P1 Mcq no. 6 and 7

AS or A2?

 

[corona]

View attachment 62963

The answer is C.

The only forces acting on an object after release are drag and gravity, but in this context drag can be ignored as the stone is thrown on the Moon, where there is no air resistance.

Hence, there is no horizontal force but a single constant vertical force (gravity) acting downwards.

 

[corona]

View attachment 62965

B.

Areas under the graph:

Cheetah: 0.5*(15+17)(29) = 464
Antelope:0.5*(14+16)(25) = 375

Distance = 100+375-464 = 11m.

 

[MShaheerUddin]

B.

Areas under the graph:

Cheetah: 0.5*(15+17)(29) = 464
Antelope:0.5*(14+16)(25) = 375

Distance = 100+375-464 = 11m.

thank u

 

[MShaheerUddin]

• A sprinter runs a 100 m race in a straight line. He accelerates from the starting block at a constant acceleration of 2.5 m s–2 to reach his maximum speed of 10 m s–1. He maintains this speed until he crosses the finish line. Which time does it take the sprinter to run the race? A 4s B 10s C 12s D 20s. Answer is C, how?

 

[xavier12]

can anyone send me A-Level Physics by Roger Muncaster pdf? I really need one to score good grades I am literally failing physics in every exam I had.

 

[Aajinkya]

Ans = D
How??

since the magnitude of them are all equal and you require a resultant torque (turning effect) i think D is right as there is upward force and a downward force so no resultant force but since 1 is acting upward from the centre and 1 is from the side they wont cancel the movement as they aint in the same direction so it'll cause a resulatant torque

 

[knowledge light]

Assalamualykum
can someone please help out
with question 3

 

[Hamnah Zahoor]

Assalamualykum
can someone please help out
View attachment 62994 with question 3

Option C is correct......(1/2k+1/2k)=1/total k
2/2k=1/Total k
Total K=k