Please Help urgently!!!!! MATHS

[scouserlfc]

AOA,

Can you please explain the geometrical circular properties and how to use them.And also explain the properties of a cyclic quadrilateral and how to use these properties to solve the question.HELP WILL BE APRECIATED,THANKS

EVEN if you dont know the whole thing but know little part of it please reply thanks....

 

[Silent Hunter]

will you understand if i just tell the properties? (in text) or you need more?

 

[scouserlfc]

ANSWER IT CMON LETS SEE WHO ANSWERS FIRST HAHAHAHA

 

[Silent Hunter]

lets wait .......... who answers first hahaha

 

[scouserlfc]

will you understand if i just tell the properties? (in text) or you need more?

Well yes indeed i would understand if you tell me the properties but explain in easy language and also tell me about cyclic quadrilateral its properties and if you can tell this by the help of diagrams it could be very easy to understand.

 

[SalmanPakRocks]

Cyclic Quad are easy here i have uploaded my diagram download it and PM me if anything is not cleared! I will be happy to help you. HERE IS THE LINK
http://www.mediafire.com/?3aw2udvlxat9cd6

I will post Circular Properties Later as Electricity will be gone shortly !!

 

[scouserlfc]

I thank you but the problem is that in the past papers if you see the the cyclic quadrilateral is divided by diagonals and then they ask to find angles if you could tell me some how i could understand but if you dont have time its not urgent since im not goin to give CIE EXAM FOR MATHEMATICS by the way really thanks for drawing the diagram.

 

[Silent Hunter]

scouserlfc: well i think i have seen them......can you tell the past papers in which they came?

 

[SalmanPakRocks]

YEah !! that is acutually the same phenomena I will post the diagonal theory tomorrow Inshahallah !!

 

[abcde]

AOA!
This explains the circle properties: http://www.nointrigue.com/docs/notes/ma ... legeom.pdf
Remember: A cyclic quadrilateral is one with its four corners lying on the circumference of a circle. In our syllabus, the only property regarding this (as far as I know) is this: angles in opposite segments are supplementary i.e. their sum always adds up to 180 I think the diagonals you see in a cyclic quadrilateral in the past papers are there to indicate two different segments, which helps you in applying the property with ease.
If you can mention a specific example, I might be able to help more.

 

[scouserlfc]

Well yes i have the example question from the past papers .ITS J03 P2 Q4 look at this question remember
heres the link...

http://www.xtremepapers.net/CIE/Cambrid ... 3_qp_2.pdf


Isnt the property of tangent other thing also mentioned in our syllabus.

 

[abcde]

Yes the tangent properties are included in the sy. I was talking only about cyclic quadrilaterals at that time. Do u want me to mention the tangent properties? What is it in this question that u don't get? Its a simple application of the properties.

 

[scouserlfc]

Yes the tangent properties are included in the sy. I was talking only about cyclic quadrilaterals at that time. Do u want me to mention the tangent properties? What is it in this question that u don't get? Its a simple application of the properties.

I KNOW ITS EASY BUT IF YOU COULD JUST SHOW ONE EXAMPLE OF HOW YOU DO IT THEN I WILL INDEED BE ABLE TO DO THIS EASILY.BUT PLEASE DONT THINK THAT I DIDNT TRY DOIN THIS I DID ALL QUESTIONS LIKE THIS FROM 1995-2005 BUT I UNDERSTOOD VERY LITTLE. SO YOU SEE

 

[SalmanPakRocks]

This Question is so easy! We just have to apply the properties but there is not tangent in this Question!

 

[abcde]

Oh, now i get what u want
Ans 4) (a) (i) AOD = 180-110= 70
ADO=DAO (base <s of isos. triangles)
=> 2ADO + 70 = 180 (< sumof triangle)
=> ADO= 55.

(ii) BAC= BDC (<s in the same segment)
=> BAC = 23

(iii) BCD = 90 (right < in a semicircle) cuz the angle subtended by a diameter at the circumference is 90!
=> CBD + 90 + 23 = 180 ( < sum of a triangle)
=> CBD = 67.

(iv) CEB = DEA
=> CEB + 90 + (23 + 55) = 180 ( we're considering triangle ADE here!)
=> CEB = 12.

I hope you get this. Try reading the properties again if not. Any further problems?

 

[SalmanPakRocks]

Oh gr8 I had the same answers !!

 

[scouserlfc]

HEY ABCDE ARE YOU GIVING MATHS IN CIE THIS YEAR WISH YOU GOOD LICK MAN AND YEAH THANKS MAN.I THINK I UNDERSTOOD JUST MENTION TANGENTS IF YOU CAN

 

[SalmanPakRocks]

What do you want to know about Tangents ??

 

[abcde]

Yes, I am. You're welcome.
A tangent is a straight line that has only one point of contact with a circle.
(i) The tangents drawn to a circle from an external point are equal.
(ii) Tangents subtend equal angles at the centre of a circle.
(iii) The line joining the external point to the centre of the circle bisects the angle between the tangents.
That's it.

 

[SalmanPakRocks]

Scouserlfc I will provide you with the diagram of every single property 2morrow so there is no confusion left !! btw I m very good at Trignometry and Bearings if u need help do tell me !!