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Post your AS-Level Mathematics (P1 and M1) doubts here.

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When is a progression convergent and even is it divergent? In p1
Convergent is when succesive values of a sequence get closer n closer to a certain number and this is when 0 < r < 1 . For example da sequnce 16/n² approches 0 as n increases.
Divergent is when succesive values of a sequence get farther apart each time n increases and this is when r > 1. for example da sequence n² keeps on increasing and increasing.
 
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Can someone please solve this, step by step:
In a geometric progression, the second term is 9 less than the first term. The sum of the second and third terms is 30. Given that all the terms of the progression are positive, find the first term.
 
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Can someone please solve this, step by step:
In a geometric progression, the second term is 9 less than the first term. The sum of the second and third terms is 30. Given that all the terms of the progression are positive, find the first term.

Given: a2 = a - 9
an = a x r^(n-1)
=> a - 9 = ar
= a - ar = 9
=> a(1-r) = 9
Given: a2 + a3 = 30
a2 = ar
a3 = ar^2
=> ar + ar^2 = 30
=> ar(1+r) = 30

Divide the 2 eqns:
ar(1+r)/a(1-r) = 30/9
the a cancels out
=> you end up with: 3r^2 + 13r -10 = 0
Solve for r: r=2/3 or r=-5
Substitute the 2 values of r in the equation: a(1-r)=9 to find a, and then use the value of a to find a2
The value of a that gives a +ve value of a2 is the correct answer
==> a=27
 
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Given: a2 = a - 9
an = a x r^(n-1)
=> a - 9 = ar
= a - ar = 9
=> a(1-r) = 9
Given: a2 + a3 = 30
a2 = ar
a3 = ar^2
=> ar + ar^2 = 30
=> ar(1+r) = 30

Divide the 2 eqns:
ar(1+r)/a(1-r) = 30/9
the a cancels out
=> you end up with: 3r^2 + 13r -10 = 0
Solve for r: r=2/3 or r=-5
Substitute the 2 values of r in the equation: a(1-r)=9 to find a, and then use the value of a to find a2
The value of a that gives a +ve value of a2 is the correct answer
==> a=27
But you can't always divide to elimate a variable right? So how can you solve the two equations using substation, and why can't we subtract to eliminate I e of the variables ? :S
 
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But you can't always divide to elimate a variable right? So how can you solve the two equations using substation, and why can't we subtract to eliminate I e of the variables ? :S
I've been able to solve every question similar to this I came across using this method. There might be another way of solving these types of questions, but i'm not aware of it, sorry. If you find a question where this method doesn't work, do post it. :)
 
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But how do you solve it by dividing the equations? :S and why can't solve the equation I originally wrote through simple elimination?
Why would you want to divide them when you can easily use elimination?
You can go ahead and try using elimination on the first question. I for one, was unable to solve using this method. There might be a different way of solving it besides dividing the 2 equations but, like I said, I don't know it. Sorry.
 
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