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Hey i have a question.........Is intensity proportional to frequency squared??
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ummm dere is no part c culd u plz check if it is da rite questionhey w11/p23 ...Q3 c(i) .....how is the striking speed 13 ,shouldn't it be 7.5 since the vertical velocity is zero?
no it is proportional to amplitude squaredHey i have a question.........Is intensity proportional to frequency squared??
itz okThanks a lot........i knew it was that.....someone else on xtremepapers confused me![]()
sorry , it was O/N 11 P21 Q3 c (i)ummm dere is no part c culd u plz check if it is da rite question
Thanks a lot........i knew it was that.....someone else on xtremepapers confused me![]()
momentum = m x vsorry , it was O/N 11 P21 Q3 c (i)
yeahAnd do stationary waves always have to be out of phase with each other?
quote="applepie1996, post: 301250, member: 29508"]ok for diffraction of transverse waves
use a laser screen and a slit and pass the laser through the slits as the light passes through the slit it is diffracted so it spreads out onto the screen showing diffraction of transverse waves
for diffraction of longitudinal waves instead of using a screen and a laser use a c.r.o to detect the sound wave and a loudspeaker as a source of longitudinal wave
momentum = m x v
=6 x 10^-3 x [–4.6 – 7.5]=0.73Ns
it aprroaches with 7.5 m/s and leaves with 4.6 in oder direction so negative
yesone thing: when the change in momemtum comes negative.... this means that its in the opposite direction? right?![]()
i got the same answer but the marking scheme uses 13m/s as approaching speed :/momentum = m x v
=6 x 10^-3 x [–4.6 – 7.5]=0.73Ns
it aprroaches with 7.5 m/s and leaves with 4.6 in oder direction so negative
no it doesnt luk at it clearlyi got the same answer but the marking scheme uses 13m/s as approaching speed :/
just move it 0.25lambda to the right that is wat i think
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