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discuss your doubts here guys..!!
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https://forum.lowyat.net/topic/992396/allformula sheet, anyone?
Both the questions are related to differentiation.In the 1st one we have been given dr/dt and he radius 50m. It is a circular patch and we have to find the rate at which the area of oil is increasing.Area of a circle is 3.142r^2.Differentiate it you will get 2pi*r.Substitute the value of r in 2pir. Than multiply it by 3 .Help please :'(
View attachment 24987
In the 2nd question you need to 1st find the value of k.Substitute M with 3.2 and r with 10 to get k.Help please :'(
View attachment 24987
Easy hyQuestion7 O/N12 paper 11 ,part ii
This is the one u will be getting there probablyCan anyone post the formula sheet?
When u differetiate for example 2(3x+3)^3Some confusions in Integration and vextors.. when you intergrate it, you increase the power and divide it by the increased power, sometimes we have to multiply the first number of the Nominator also,, aswell as in integration. Help?
Help please :'(
View attachment 24987
JazakAllahEasy hy
For finding n first
Remember cos sq theota =1-sinsq theota
Apply it and make the equation
2sinsq ntheota + 3sin ntheota - 2 =0
Solve it quadratic
U get sinn theota =0.5. And =-2
Ignore -2 as it will give math error
Ok now when u solve for sin theotA=0.5 u get ntheota= (1st and 2n quad) 30,150
It says for the minimum POSITIVE value theota =10
Ntheota=30 , 10n=30 , n=3
This n will remain constant
Now the next part it says the largest value in 0-360
For sin 3theota find the values they will be
30,150,390,510,750,870 ( add 360 2 times as there will be three rotations as its 3 theota)
Now divide by 3 largest number in 360 range is 870/3=290
No likes needed just pray we all get straight a*
Hey its easy bro just remember the concept of sin graph
the equation y=asin(bx)+c in every sin graph will mean
a=amplitude , in this case 9-3 =6
b=no of complete wave in 2pie (360 degrees) , in this case 2
c=the mean point where wave is starting , in this case 3
so it becomes
6sin2x+3=y
for the second part put y=0
u will get sin2 inverse = -0.5
ignore - and take sin in the opposite quadrants (2,3 )
now for sin2 inverse 0.5 u get 30
2nd quad
180-30=150
3rd quad
180+30=210
so you have two values 150,210 WAIT , remember it was sin2theota ? , divide it by 2
u get 75 and 105 least is 75 , thats ur answer if u dont understand ask me ,
Both the questions are related to differentiation.In the 1st one we have been given dr/dt and he radius 50m. It is a circular patch and we have to find the rate at which the area of oil is increasing.Area of a circle is 3.142r^2.Differentiate it you will get 2pi*r.Substitute the value of r in 2pir. Than multiply it by 3 .
dA/dt=dA/dr *dr/dt
First of all remember if A=bk ( k constant )
Then rate formula is
DA/DT = DB/DT multiply DB/DA
IN FIRST QUESTION FORMULA WILL BE A=pie r^2
Find DR/DA
2pie r =Da/dr
Now the formula for this is
Da/dt = dr/dt multiply dr/da
Radius increasing at 3 when initial is 50
Da/dt=3 x 2 pie (50)
=300 pie is answer
For second question apply the same with that formula find the value of k by putting values
M=kr^3
3.2=10^3k
K=o.oo32
If u dont get any part do let me know before the paper
100% right , i mixed it with cosine , my badbro isnt the 4 quadrant thing like this S | A
T | C
With S being taking Sin as positive, A as all being positive, C being cos postive and T being tan positive. SO when you worked out the quadrant, why did you use S and T - 180 + x (s) and 180 - X (t) . Shouldnt it be 180 + x (T) and 360 - x (C) since you get a negative value??
same ?? how?100% right , i mixed it with cosine , my bad
Answer same hy ittefak se
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