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ajmaeen said:
Last part couldnt be 14.. it would be 126+14 !! .. !! Beacuse pink with other colors also satisfy the condition given !!!!
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S1 paper6 how was it????
- Thread starter darkism
- Start date
Last part couldnt be 14.. it would be 126+14 !! .. !! Beacuse pink with other colors also satisfy the condition given !!!!
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I get 1 mark in the last part !!!and i lose my mark there.. i wrote 126 +1 :mrgreen: :mrgreen: :mrgreen:
Dont know y i put 1 there.. lol
Dont know y i put 1 there.. lol
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You had to use a combination (lol excuse the pun 
) of combinations and permutations.
Like, for the question that asked for all the possible selections of 3 cards from the 9 cards and there arrangements, you had to write:
(9C3)*(3!)
9C3 gives all the possible combination of the three cards NOT focusing on their order. 3! to include the 6 possible positions of each of the three pairs.
) of combinations and permutations.Like, for the question that asked for all the possible selections of 3 cards from the 9 cards and there arrangements, you had to write:
(9C3)*(3!)
9C3 gives all the possible combination of the three cards NOT focusing on their order. 3! to include the 6 possible positions of each of the three pairs.
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Agreed.. !! Max is 41.. it doesnt go abv it
What was the answer to the second last part of the last question?apple said:You had to use a combination (lol excuse the pun
Like, for the question that asked for all the possible selections of 3 cards from the 9 cards and there arrangements, you had to write:
(9C3)*(3!)
9C3 gives all the possible combination of the three cards NOT focusing on their order. 3! to include the 6 possible positions of each of the three pairs.
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Oh ma god!!!! da paper was horrible))))) Examiner is a _________________________ literally!!!! But no matter I will score good in P3 thatz 4 sure and my M1 & P1 also went gr8.but S1 !!!!
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the second last was 168 i think though i dunt remember specifically. .:s
for me nice one
hey that question cant be done with binomial..... no constant probab. of success.... and yeah it was mutaully exclusive as p(q and r)=0
and the permutation thing was to my knowledge not that difficult
last answer was 504-28=476 ways ,.....wooo it was a superb exam!!!!!!!!!!!!!!!!!!!!!!
hey that question cant be done with binomial..... no constant probab. of success.... and yeah it was mutaully exclusive as p(q and r)=0
and the permutation thing was to my knowledge not that difficult
last answer was 504-28=476 ways ,.....wooo it was a superb exam!!!!!!!!!!!!!!!!!!!!!!
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very bad paper. the permutaion was bad. what are mutually exclusive and independent junks.
ajmaeen said:
dude it wasnt 14...jus lemme giv u an example...wat if neither green nor pink was selected...even then the pink n green wudnt be together cuz they r not selected at all...so like wise pink alone cud be selected n not green..n green alnone can be selectd n not pink...n both can be selectd...so da answer was 476!
n both permutation n combination cud be slectd depending how u tackle the question...fr example fr the last q 3rd last part, by using permutation it cud be 9P3 n by using combination it wud be 9C3x3!...both r correct...cuz once u hav chosen the 3 cardz frm 9, u also hav to arrange them in a line so 9C3x3! is also correct
Paper was definitely of above average difficulty, but mine went well, nonetheless. Only made a couple of mistakes. One was that I forgot to subtract P(X=0) from 1 in Q2 and another one in Q4(ii). So expecting 45+. Permutation's questions last part was 476. It was a good question.
Here are the answers:
1(i) SD = 12.3
(ii) Median
(iii) Not mean because it would account for an exceptional case (48) and not mode because data does not have enough repeating values.
2(i) 0.854
(ii) 0.215
3. Country B had a higher median and the weights were more spread out.
4(i)0.95
(ii) Mu = -1.57(sigma)
5(i) 1/24
(ii) 1/9
(iii) Mutually Exclusive, because both events cannot happen simultaneously.
(iv) Not independent since P(Q) x P(R) =/= 0
6(i) 0 - 1/7, 1 - 4/7, 2 - 2/7
(ii) Variance = 20/49
(iii) 5/32
7(i) 9!
(ii) 282240
(iii) 504
(iv) 168
(v) 476
1(i) SD = 12.3
(ii) Median
(iii) Not mean because it would account for an exceptional case (48) and not mode because data does not have enough repeating values.
2(i) 0.854
(ii) 0.215
3. Country B had a higher median and the weights were more spread out.
4(i)0.95
(ii) Mu = -1.57(sigma)
5(i) 1/24
(ii) 1/9
(iii) Mutually Exclusive, because both events cannot happen simultaneously.
(iv) Not independent since P(Q) x P(R) =/= 0
6(i) 0 - 1/7, 1 - 4/7, 2 - 2/7
(ii) Variance = 20/49
(iii) 5/32
7(i) 9!
(ii) 282240
(iii) 504
(iv) 168
(v) 476
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did the most _____________ mistake ever, used binomial in probability distrib. WTF!
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just came to know dat I have almost lost 11 marks