S1 paper6 how was it????

[sweetie ♥]

@sweetie
Yes the last one was of 10 !!
And i dunt get it which question u talking abt ?

it waz the second last part of the last Q ......

 

[ashhadazam]

I got 168 to that one !!!

 

[sweetie ♥]

cn u show me da way plzzzz!!!!!

nd for the relatinship bw mew and SD , my Z value was wrong , so ma ans. waz also wrong , how many marks do u think i wud luz????
thanx 4 da reply!

 

[hampard19]

its was soo easy......though i had a little problem in question 4........but besides dat everythng went awsome!........permutaion and combination was very easy!!.....

one small step for man.....one giant STUMBLE mankind

 

[sweetie ♥]

show me hw u got 168, sum1 plzzzzzz!!!!!!!!!

 

[safdad]

it was quite simple to do u had to use combination in the last 2 parts of Q7

 

[princesszahra]

combination ques was just ok for me
rest was awesome

 

[Jazib]

Here are the answers:

1(i) SD = 12.3
(ii) Median
(iii) Not mean because it would account for an exceptional case (48) and not mode because data does not have enough repeating values.

2(i) 0.854
(ii) 0.215

3. Country B had a higher median and the weights were more spread out.

4(i)0.95
(ii) Mu = -1.57(sigma)

5(i) 1/24
(ii) 1/9
(iii) Mutually Exclusive, because both events cannot happen simultaneously.
(iv) Not independent since P(Q) x P(R) =/= 0

6(i) 0 - 1/7, 1 - 4/7, 2 - 2/7
(ii) Variance = 20/49
(iii) 5/32

7(i) 9!
(ii) 282240
(iii) 504
(iv) 168
(v) 476

welll comparing my answers n "assuming" these answers are correct, im only loosing 4 marks

 

[a2man]

Dude for the last part of 1st question, i wrote "not mode b/z there is not a significant frequency of its occurrence (10 occurs only 2times) and that its deviation from other numbers is greater than of median." is it correct too?

 

[princesszahra]

i hate permutations!

 

[x+y=z]

about the last question of permutations....for the number of PINK cards in that 504 sets. i did it like this..probability of picking up a pink card 1/9. so ( 1/9 * 504 = 56 ) SO 56 sets out of 504 will have pink in it.
Can any one tell me wats wrong in it? :?:

 

[ahsanxr]

about the last question of permutations....for the number of PINK cards in that 504 sets. i did it like this..probability of picking up a pink card 1/9. so ( 1/9 * 504 = 56 ) SO 56 sets out of 504 will have pink in it.
Can any one tell me wats wrong in it? :?:

It asked about the arrangements. 56 sets contained P. Multiply that by 3 to find the total arrangements.

 

[Hamdiii]

my all answers are correct except the las qustion's last 3 parts...
how many marks im gonna lose??

 

[ashhadazam]

Bad news guyz.. !!! The events were mutually exclusive but not independent !!!
I searched it on net about probabilities and i finaly found that two events could not be both mutually exclusive and independent simultaneously...

Either it could be exclusive or independent or none.. !!! so Some of us lose marks here COngrats i lose them too

 

[princesszahra]

haha then mine is correct
it isnt a bad news for me!

 

[sse2010]

yipee!!! neither fr me

 

[ashhadazam]

It is bad for me.. and for many others

 

[Jazib]

Bad news guyz.. !!! The events were mutually exclusive but not independent !!!
I searched it on net about probabilities and i finaly found that two events could not be both mutually exclusive and independent simultaneously...

Either it could be exclusive or independent or none.. !!! so Some of us lose marks here COngrats i lose them too

thnx a lot, dat really helped! cuz it was mutually for sure, so not independent

 

[ashhadazam]

Dat really helped for u.. My friends are cursing me for this ...ahahahah

 

[Jazib]

1st I wrote not independent, went to solve other questions, then i cut dat, n wrote independent, completed my paper n then when the supervisor said stop writing, i again cut it, n wrote not independent