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urgent help plzz maths
- Thread starter hm12
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Well that's very simple. Firstly you should call it "Square Root" and not under root because that is the proper term.
Secondly convert the term like this:
[5x+4]^1/2 <<< that's to the power one by two/half.
Now you can use the formula:
(function)^n >>> n(function)^n-1 MULTIPLIED BY (derivative of function)
Give it a try and post your result!
Don't forget to click the Thanks Button!
Secondly convert the term like this:
[5x+4]^1/2 <<< that's to the power one by two/half.
Now you can use the formula:
(function)^n >>> n(function)^n-1 MULTIPLIED BY (derivative of function)
Give it a try and post your result!
Don't forget to click the Thanks Button!
- Messages
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- Reaction score
- 32
- Points
- 28
its a simple question........
first change the given equation into y=(5x+4)^1\2 which is in the form of (ax+b)^n
and we do have the formula of differentiating such equation with a general formula,
dy\dx = n(ax+b)^n-1 * a
Similarly in the above case you would get its differentiation as
dy\dx = 1/2(5x + 4)^-1/2 * 5
i.e. dy\dx = 5\2(5x + 4)^1/2
thats it but remember that such general formula can b applied only in the case of (ax + b)^n........ not in other case!!!!!!!!!!!!!!
first change the given equation into y=(5x+4)^1\2 which is in the form of (ax+b)^n
and we do have the formula of differentiating such equation with a general formula,
dy\dx = n(ax+b)^n-1 * a
Similarly in the above case you would get its differentiation as
dy\dx = 1/2(5x + 4)^-1/2 * 5
i.e. dy\dx = 5\2(5x + 4)^1/2
thats it but remember that such general formula can b applied only in the case of (ax + b)^n........ not in other case!!!!!!!!!!!!!!
