nope the answer for GP was a=27what about the G.P? did anyone get a=14?
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nope the answer for GP was a=27what about the G.P? did anyone get a=14?
aur shahab kia haal hain ?nope the answer for GP was a=27
yur dy/dt is wrong3) a=5 ,, trigonometry angles were 45 & 116.6 ,,, 9) area was 28/3,, 10) k<0 or k>64/9 ,,, 2) dy/dt was 0.12*7/8 ,, i was unable 2 solve ap & gp
3 marksguys in Q9 i correctly calculated A but i miscalculated B
hw many marks will i lose ?
dude dy/dt was 0.105yur dy/dt is wrong
its 0.015
haha yeh sry i meant that...dude dy/dt was 0.105
the lenght of CD was 2.5 , i thinkWhat was the answer for the question which asked to calculate the length of CD?
does anyone remember the coordinates of A and B (which was given in the question)?
thanks
The coordinates of A and B??the lenght of CD was 2.5 , i think
srry friend, not able to recall.The coordinates of A and B??
yup it was..the lenght of CD was 2.5 , i think
if u r length is 2.5 then ur coordinates should be rytThe coordinates of A and B??
the second term if a GP is 9 less than the first term. The sum of the second and third terms is 30. Given that all terms are positive*, find the value of the first term.
a.r = a - 9 ; a.r + a.r^2 = 30
>> r = (a - 9)/a
>> 30 = (a - 9) + a.[(a-9)/a]^2
>> 30 = a - 9 + (a-9)^2/a
>> 39.a = (a^2) + a^2 - 18.a + 81
>> 2.a^2 - 57.a + 81 = 0
>> factorize to get (a - 27)(2.a - 3) = 0
a = 27 or a = 3/2
since r= -5 when a= 3/2, the terms become negative*(see question);
Ans: a = 27
ok thats wat i meant 2 but i 4got the value 7/8 * 0.12 = 0.105haha yeh sry i meant that...![]()
i am doing statistics, it's on the 24th of mayanybody for as level statistics here.
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