Paper 12 maths

[Aarjit]

i made a mistake in finding the shaded area in integration, i got 1 limit correct but the other was wrong but i showed all the steps would i get any marks for it (if any then how much out of 4)

I think you're referring to Q9 here, the one with A(4,6) and B(2,2).
You'll lose the A1 mark + a mark for miscalculating B(2,2) ~ 2 marks.
Albeit, you'll get the e.c.f. mark for the area.

 

[shabby]

what about the G.P? did anyone get a=14?

nope the answer for GP was a=27

 

[shayreeikg]

nope the answer for GP was a=27

aur shahab kia haal hain ?

 

[cheesww]

guys in Q9 i correctly calculated A but i miscalculated B
hw many marks will i lose ?

 

[cheesww]

3) a=5 ,, trigonometry angles were 45 & 116.6 ,,, 9) area was 28/3,, 10) k<0 or k>64/9 ,,, 2) dy/dt was 0.12*7/8 ,, i was unable 2 solve ap & gp

yur dy/dt is wrong
its 0.015

 

[rose1700]

guys in Q9 i correctly calculated A but i miscalculated B
hw many marks will i lose ?

3 marks

 

[uberleet]

if I get 55/75 in P1 do I have any chance of A grade overall? How much would I need in M1?

 

[shanky631]

yur dy/dt is wrong
its 0.015

dude dy/dt was 0.105

 

[cheesww]

dude dy/dt was 0.105

haha yeh sry i meant that...

 

[hamzasalam]

What was the answer for the question which asked to calculate the length of CD?
does anyone remember the coordinates of A and B (which was given in the question)?
thanks

 

[fathimaash]

2.5 i think

 

[Farah1996]

24 hours passed olready, lets discuss it

 

[shanky631]

What was the answer for the question which asked to calculate the length of CD?
does anyone remember the coordinates of A and B (which was given in the question)?
thanks

the lenght of CD was 2.5 , i think

 

[shanky631]

anybody for as level statistics here.

 

[hamzasalam]

the lenght of CD was 2.5 , i think

The coordinates of A and B??

 

[shanky631]

The coordinates of A and B??

srry friend, not able to recall.

 

[user]

the lenght of CD was 2.5 , i think

yup it was..

 

[fathimaash]

The coordinates of A and B??

if u r length is 2.5 then ur coordinates should be ryt

 

[gadagada]

the second term if a GP is 9 less than the first term. The sum of the second and third terms is 30. Given that all terms are positive*, find the value of the first term.

a.r = a - 9 ; a.r + a.r^2 = 30
>> r = (a - 9)/a

>> 30 = (a - 9) + a.[(a-9)/a]^2
>> 30 = a - 9 + (a-9)^2/a
>> 39.a = (a^2) + a^2 - 18.a + 81
>> 2.a^2 - 57.a + 81 = 0
>> factorize to get (a - 27)(2.a - 3) = 0

a = 27 or a = 3/2
since r= -5 when a= 3/2, the terms become negative*(see question);

Ans: a = 27

 

[Sanis]

haha yeh sry i meant that...

ok thats wat i meant 2 but i 4got the value 7/8 * 0.12 = 0.105