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We know that alpha( the intensity reflection coefficient ) is also = Ir/I
We need Ir
We got alpha in first part 0.33. From second part, I2=Ie^-ux
But since it's received back at the surface, it travelled twice the thickness, so it's 2x now.
So Ir= apha(I2)=0.33(0.39^2)(I)
This is why we square the fraction in part two.