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  1. A

    clash in 9700/22 and 9700/52? wtf!

    why u so surprised all sciences have clashes between p2 and p5
  2. A

    GrAdE threshold

    usually about 17-22
  3. A

    Mechanics help needed

    yep but it must be caught at the same hieght this is because the acceleration is always the same goin up and the same goin down
  4. A

    Mechanics help needed

    q28 well time taken goin up is the same as time taken comin down so it will take 1.5 seconds to rise and another 1.5 to fall now use s=0.5at^2 a here is 10 t is 1.5 ie time taken to fall that will give u...
  5. A

    Mechanics help needed

    different notes may have different approaches to questions oh are u takin Alevel or As
  6. A

    Mechanics help needed

    if u need anything else im here to help
  7. A

    MATHS P12

    exactly
  8. A

    Mechanics help needed

    23 C)well u find out how much it falls in three seconds which will be 45m and then minus it from how much it travels in two seconds which is 20 which will be 25 remember they want it during THE third second and not during THREE seconds
  9. A

    Mechanics help needed

    back to Q16 ii)now we have to all we do is replace it into the equation t=10/a iii)well 40 seconds before it comes to rest we know the last 40 seconds are in the decceleration part and we can calculate the decceleration part to be 120 seconds so the time it travels while deccelerating is...
  10. A

    Mechanics help needed

    some ansers are wrong in the book im sure of my anser my teacher cheked it
  11. A

    Mechanics help needed

    16)well first we must show that decelerating time is 6 times more than accelerating time for accelerating part we know that a=10/t so the accelerating time is t=10/a as for decceleration we know 0.5a=30/T (notice the capital T) so T=60/a soooo deccelerating time T is six times as much as t now...
  12. A

    Mechanics help needed

    14i) from about 10 to 25 the straight line segment cause it has the highest gradient
  13. A

    Mechanics help needed

    gd made a few silly mistakes in simeltaneous equations and one tiny mistake in the last question alrest was fine
  14. A

    Mechanics help needed

    t=15 it is in the CD segment and as u see is a horizontal line so Zero t=25 it is in the EF segment so all we do is find out the gradient and that will be -0.15 the tV graph from T=0 to T=3 ther is a straight line with a positve gradient then from 3 to 11 it is a straght line then from...
  15. A

    Mechanics help needed

    for 13c its zero since the graph is horizontal line there is no movement hence no velocity 15) wen t is 5 it is in the AB straight line segment. ie the speed is the gradient of this straight line u can find out the gradien using the points of A and B it should be 0.178
  16. A

    Mathematics 9709 paper 12 how was it with you?

    i hope mechanics and statistics go well cause im aiming for an A* i made only 2 silly mistakes in this exam one in simeltaneous and another in last question and im really pissed cause i had the time to revise but i didnt bother
  17. A

    Mechanics help needed

    found it post ur doubts here!
  18. A

    Mechanics help needed

    have u noticed that we both got ranked up to elite lately
  19. A

    Mechanics help needed

    ye thnx i got that one correct did u get my explanation?? sorry but im hunting for the nabeel elias book cant seem to find it!!!!
  20. A

    Mechanics help needed

    wat was the anser for the first question u asked
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