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How to convert binomial distribution to normal distribution?
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this is how u do it....if m not mistaken
since no P's should be included but either an S or two S's u'll have to choose 4 letters from the word HAINE
first option one S should be included, so u can have options like HAIS or HINS or HNSE etc, hence number of ways would be 5C3
second option, both S's should be included, so u can have options like HASS or HISS or HNSS etc, hence choosing 4 letters u'd have 5C2
now add both u'll get ur answer as 20.
hope i was clear enough
syed1995 nd Champ101
somebuddy plz explain this
Find the number of different ways in which the 9 letters of the word GREENGAGE can be
arranged if exactly two of the Gs are next to each other.
ur welcomethanks a lot. yoou r real genius
How to convert binomial distribution to normal distribution?
y r u not considering 3! for GsStick 2 Gs together and permute A(GG)EEENR then fit in the 3rd G so that it is not
next to (GG). There are 6 possible places. Total number of perms is [7!/(3!)]6=5040.
Find the number of different selections of 4 letters from the 9 letters of the word HAPPINESS which contain no Ps and either one or two Ss.
How to solve this one?
y r u not considering 3! for Gs
no no_ A (GG) E _E_E_N_R_
6 7 3 2 5 4 3 2 1
6 X ((7x3x2x5x4x3x2x1)/3!) = 5040
no no
m telling that there are also three Gs
so y it shoud not be [7!/(3!x3!)]6
one 3! for Es and another for Gs
its a good question
one should solve this
A fair five-sided spinner has sides numbered 1, 2, 3, 4, 5. Raj spins the spinner and throws two fair
dice. He calculates his score as follows.
• If the spinner lands on an even-numbered side, Raj multiplies the two numbers showing on
the dice to get his score.
• If the spinner lands on an odd-numbered side, Raj adds the numbers showing on the dice to
get his score.
Given that Raj’s score is 12, find the probability that the spinner landed on an even-numbered side.
use conditional probabilty P(even/score12)= (2\5 * 4\36) /(4/36)?its a good question
one should solve this
A fair five-sided spinner has sides numbered 1, 2, 3, 4, 5. Raj spins the spinner and throws two fair
dice. He calculates his score as follows.
• If the spinner lands on an even-numbered side, Raj multiplies the two numbers showing on
the dice to get his score.
• If the spinner lands on an odd-numbered side, Raj adds the numbers showing on the dice to
get his score.
Given that Raj’s score is 12, find the probability that the spinner landed on an even-numbered side.
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