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AS Physics P1 MCQs Preparation Thread.

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The uncertainty (accuracy) in this result is 3%
First calculate it: It's 9.8298
U must remmbr that uncertainties are ALWAYS written correct to 1 SF!
So, the above correct to 1 SF is:
10
Uncertainty will be 10 m/s
Also, remmbr that the calculated answer (speed 327.66 u have), is DEPENDENT on the uncertainty.
I mean that the decimal places (or accuracy in this case) of the speed is determined by the uncertainty.
Uncertainty (accuracy - and let's refer them to be the same thing here for now), is 10.
So speed will be correct to 10m/s

ie 330m/s

That is all.
SO:
Find uncertainty first.
Make it correct to 1 sf
Write calculated value correct to the uncertainty.

eg:
X = 34.5444 m
Uncertainty = 0.00498 m
Make uncertainty 1sf = 0.005m
Write X correct to the uncertainty ie 3dp
X = (34.544 +/- 0.005) m

Tadaa
Thanks a lot for the explanation!!

Are you sure that the uncertainty is always written to 1 s.f?? I think I have seen cases where the uncertainty is written to more than 1 s.f
 
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explain winter11 paper 11 question5

find fractional uncertianities in all the values.
Length:eek:.oo2/2.043
diameter:2 multiply 0.00002/0.00054
take out for force also.largest is in diameter so it is the answer.remember to take length in one same unit.
 
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Ea7gn9N.jpg



This question
 
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Okay, someone KINDLY tell me everything about stationary waves!
Including the waves formed in open-ended, or closed tubes etc.
I'll be extremely grateful!
 
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Physic As oct 2010 / 12 mcq 22 and 34
May 2011/12 mcq 15,16,24
Pleasesss
22:
Look, k is a measure of the stiffnes of the spring.
So the gr8er the k, the STIFFER the spring.
Likewise, lower the k, the less stiff, or more bendy the spring.

In B, low k (bendier) has a stiffer (high k) spring attached to it.
Imagine. The bendier is being pulled by a stiff, rigid-ish spring WITH a load attached to it!
It's like there are two people hanging by the horizontal pole in a circus.
The one with the weaker limbs is being held onto by the one with stronger ones!
The weaker person will be pulled - A LOT! And may even break a limb!

So just apply this concept to the strings.
In B, too much load on the bendier, weaker spring. It'll break.

In D, for the equal load, both springs will NOT be stretched by same extension.
High k (stiff remmbr?) will be stretched less and weaker (low k) will be more stretched.
The board will be uneven.

Now it's either A or C.

C is illogical. Why would u want to support the stiffer spring or maybe stronger person in the circus? There's no need!

A's the one.
U support the weaker spring so when the heavy load and stiff spring is attached to it, it won't "break a limb".

This was long but I couldn't think of any other way.
 
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M/J'12 : Q.4,17,18,20,24,26,29,30,35,37,38
O/N'12 :Q.8,12,13,14,16,17,18,19,22,26,30,31
O/N'11 :1,2,7,9,10,11,12,14,15,17,21,23,26,28,31,33,34,35,38,39
plzzz someone help me..
 
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Somebody please helppppppppp these are my problems don't have any link pls
Physic As oct 2010 / 12 mcq 22 and 34
May 2011/12 mcq 15,16,24
May 2011/ mcq 14,15
Oct2011/13 mcq 17,25
Oct 2011/12 mcq 26
May 2012/12 mcq 5
 
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To find maxima you use dxSin90= (no. of maxima) x (wavelength)
-To find 'd' we use 1/no of lines
-so 1/300= 3.3x10^-3
-Since 'd' is in mm change wavelength to mm as well which becomes 6.9x10^-4
- No put the values in eq: (3.3x10^-3) x (1) = (No. of maxima) x (6.9x 10^-4)
And you get 4.87, round it off to 5

Hope I helped!
 
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