AS Physics P1 MCQs Preparation Thread.

[Sajeeb Chowdhury]

some
somebody solve this thinng!! PLEASE

the link is https://www.facebook.com/sajeebchowdhury

 

[rockerkunal]

how the poop is the answer D? just how? helpp!

 

[Obsidian Fl1ght]

this qn! http://i.imgur.com/Ea7gn9N.jpg

U gotta learn this... it's simple. Just learn it right now.
K-capture is the opposite of a normal Beta emission.
In normal beta reaction:
n ---> p + e

In K-capture:
e + p ----> n

So... remove a proton, 28 - 1 = 27 (Proton No.)
And add a neutron.
Look at the Nucleon number: 59 (Remove a proton) - 1 (Add a neutron) + 1 = 59

And the winner of this round is:
C.

Got it?

 

[salvatore]

Thank u immensely.

Best of luck yeah u too!

Btw, one final question: w12/qp12/q10...
Can u explain the logic?

The man's motion is a projectile; hence, the horizontal component is always constant and the vertical component is the one that changes. This means that velocity can never be zero since there is a non-zero horizontal component that never changes. So C is ruled out!
A can not be the answer because it shows that velocity increases then decreases, but in the real sense, the velocity will decrease first since the skier is moving upwards against gravity and then it will increase.
Hence, B and D are the only options left. I'm not sure of this part of the explanation, but this is what I think:
The acceleration/deceleration is not constant and therefore, B can not be the answer due to the straight line gradient which represents constant acceleration.
So the answer is D

 

[Obsidian Fl1ght]

there ya go.... when's ur xm....... if u need ny help just add me on fb.... the id is [email protected]

oh nd YM = young modulous
str = stress

Thanx loads man.
But I don't get how u got 1/16???
Explain?

 

[rockerkunal]

U gotta learn this... it's simple. Just learn it right now.
K-capture is the opposite of a normal Beta emission.
In normal beta reaction:
n ---> p + e

In K-capture:
e + p ----> n

So... remove a proton, 28 - 1 = 27 (Proton No.)
And add a neutron.
Look at the Nucleon number: 59 (Remove a proton) - 1 (Add a neutron) + 1 = 59

And the winner of this round is:
C.

Got it?

thanks a KABAGILLION! thanks man

 

[Lyfroker]

how the poop is the answer D? just how? helpp!

I expect it to be C :S

 

[Obsidian Fl1ght]

The man's motion is a projectile; hence, the horizontal component is always constant and the vertical component is the one that changes. This means that velocity can never be zero since there is a non-zero horizontal component that never changes. So C is ruled out!
A can not be the answer because it shows that velocity increases then decreases, but in the real sense, the velocity will decrease first since the skier is moving upwards against gravity and then it will increase.
Hence, B and D are the only options left. I'm not sure of this part of the explanation, but this is what I think:
The acceleration/deceleration is not constant and therefore, B can not be the answer due to the straight line gradient which represents constant acceleration.
So the answer is D

Thanx!
The CIE guys sure know how to knock u out with those graphs!

 

[rockerkunal]

ih

I expect it to be C :S

oh wait yea its C, i forgot.. but why is it C i was expecting it to be a B since acceleration is contant as g?

 

[Obsidian Fl1ght]

ih
oh wait yea its C, i forgot.. but why is it C i was expecting it to be a B since acceleration is contant as g?

Yeah... acceleration is constant ie g... when the object's only being acted upon by GRAVITY!
SInce it's a tallll building, there MUST b some Air resistance.
Then cometh the usual AR incr. --- Vel. Incr. --- Acc. decr. to zero ---- terminal velocity and the rest.

 

[Obsidian Fl1ght]

Okay anyone, w12/12/31 ---- HOW is it a radio wave and not micro wave???

 

[Sajeeb Chowdhury]

how the poop is the answer D? just how? helpp!

which year is this......

 

[rockerkunal]

Yeah... acceleration is constant ie g... when the object's only being acted upon by GRAVITY!
SInce it's a tallll building, there MUST b some Air resistance.
Then cometh the usual AR incr. --- Vel. Incr. --- Acc. decr. to zero ---- terminal velocity and the rest.

crap! those trixy little cie people! smh.. thanks a ton man

 

[Martee100]

Hey can someone help me with this

 

[Manobilly]

Good Luck every 1

 

[Sajeeb Chowdhury]

Okay anyone, w12/12/31 ---- HOW is it a radio wave and not micro wave???

read this http://science.hq.nasa.gov/kids/imagers/ems/waves3.html

 

[Martee100]

This question

 

[lee mee..]

Can someone please explain me how to do Q24..​

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_11.pdf

 

[rockerkunal]

Hey can someone help me with this

eassy! you draw the triangle, take tan, tan30=x/0.15, solve for x, you willl get it

 

[rockerkunal]

This question

woke done= kinetic energy, =0.5 x m x v^2, 0.5 x 800x1000 x 50^2 = 1x10^9 J