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AS Physics P1 MCQs Preparation Thread.

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could ny 1 please solve this.... :)

View attachment 28839
use the equation nλ=dSinθ where n(number of order), λ(wave lengeth), d(distance between each grating) and θ being the angle.
since he's looking at the maximum number of images so Sinθ= 1. and nλ=d.
to find d, you divide 1mm/500 so you get 2x10^-6/
n=d/λ=2x10^-6/(600x10^-9)= 3.33 on each side of the zero order
so you add 3+3 to find images on both sides of Y and add the zero order line which also forms an image. so 3+3+1=7

oops somebody already answered
 
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lol sorry for that. Good luck for the exam today hope you do very well :D
Haha no harm done.
U admitted ur mistaken-ness and that, my friend, means u've got guts.
:D
Technnically speaking, everyone here HAS guts... but yeah u get the point.
U too!!!
 
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answer is D, because only points within the overlap are in phase and so A and C are wrong. also B is wrong because stationary waves have varying amplitudes.

thanks
so u mean to say from N1 TO N2 point ass in phase then from n2 to n3 is it?
 
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27 shd b A.
No. 1. Nodes are always formed at closed ends so discard D.
No.2 In one loop, ie between two nodes, particles are in phase. WITHIN one segment. (Or loop)
So particles r in phase, one direction, in bottom segment.
Particles are in phase in second (top) segment. BUT particles in bottom and top segments ARE NOT in phase with EACH other.
I hope u get what I mean.
Amplitude of particles equidistant from a node is same.
So A.
 
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27 shd b A.
No. 1. Nodes are always formed at closed ends so discard D.
No.2 In one loop, ie between two nodes, particles are in phase. WITHIN one segment. (Or loop)
So particles r in phase, one direction, in bottom segment.
Particles are in phase in second (top) segment. BUT particles in bottom and top segments ARE NOT in phase with EACH other.
I hope u get what I mean.
Amplitude of particles equidistant from a node is same.
So A.

yes, i understood. thank you.
 
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