- Messages
- 175
- Reaction score
- 91
- Points
- 38
d sin thetha = n lamida
d = 1/n, n = lines/m
So n = 500 * 1000 lines/m
d = 1/n = 1/500,000
thetha take 90
lamida is 600 * 10 ^-9 m
Find n.
n is 3.33 ie 3 complete images on one half of screen.
On both halves = 3 * 2 = 6
But u also have to consider central maxima.
So total maximas (images) is 6 + 1 = 7