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Chemistry 42....how did it go?..expected GT

histephenson007

histephenson007

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leadingguy said:
hahaha gr8 I think i did the same and on the very net page the isomers were????/ secondary and tertiary alcohols!!!!!!!!!
I gues?????
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I think there could be many possible answers for that question. However, the compound is already a tertiary alcohol, so I doubt whether another tertiary alcohol could be an isomer.
 
umarashraf

umarashraf

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i thought it was a good paper... i have more mistakes in p2 than i did in p4.... Apart from App, pap went excellent...:) hoping around 75 to 80...
 
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Sannikutti

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histephenson007 said:
Juglone doesn't have an ester, but compound D does.
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U can make isomer of that with the Juglone cuz it has an OH group :D
But my point wasnt that my point was that they said have same functional groups but at different position rite they said in the question
So it was positional isomerism u get me?So u shift the OH to other place so it becomes different Isomer with Different position of ester which gives different position of ester got it ?
 
histephenson007

histephenson007

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Sannikutti said:
U can make isomer of that with the Juglone cuz it has an OH group :D
But my point wasnt that my point was that they said have same functional groups but at different position rite they said in the question
So it was positional isomerism u get me?So u shift the OH to other place so it becomes different Isomer with Different position of ester which gives different position of ester got it ?
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no dude, I remember the question particularly mentioning that the bonds were in the same location. So, I remember that for certain this should be a Stereoisomer, but I just couldn't figure out which type. Finally, I just drew a mirror image :)
 
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Sannikutti

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histephenson007 said:
no dude, I remember the question particularly mentioning that the bonds were in the same location. So, I remember that for certain this should be a Stereoisomer, but I just couldn't figure out which type. Finally, I just drew a mirror image :)
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I am sure ur rite.Can u draw the transor cis of that pls kindly or trans of that if it is cis already.Because rotation along the double bond is not possible if the two cyclic molecules are attached,but still draw and kindly upload i dint drew it.
Btw first criteria of the optical isomer is chiral carbon which due to having double bond it will not be chiral so u cnt reflect it.
Afterall all the isomers of lawsone is listed by wikipedia if u refer to the website it will mention.
Even i dint draw it right.
Enought was the crohmate enought -this one i got 0.9somethjng
where are u givin the exam? my be we were in same center or country or may be not if u like tell only no force.
 
histephenson007

histephenson007

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Sannikutti said:
I am sure ur rite.Can u draw the transor cis of that pls kindly or trans of that if it is cis already.Because rotation along the double bond is not possible if the two cyclic molecules are attached,but still draw and kindly upload i dint drew it.
Btw first criteria of the optical isomer is chiral carbon which due to having double bond it will not be chiral so u cnt reflect it.
Afterall all the isomers of lawsone is listed by wikipedia if u refer to the website it will mention.
Even i dint draw it right.
Enought was the crohmate enought -this one i got 0.9somethjng
where are u givin the exam? my be we were in same center or country or may be not if u like tell only no force.
Click to expand...
Ok ok, if u did so much research then it should probably be right.
Wasn't E-naught for Chromate +1.33 or something like that?
I'm giving the exam from China :p
 
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Sannikutti

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histephenson007 said:
Ok ok, if u did so much research then it should probably be right.
Wasn't E-naught for Chromate +1.33 or something like that?
I'm giving the exam from China :p
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well ya it was 1.33 but the formula is
some of oxidation potential and reduction potential
They said it oxidises the A to get lawsone
so chromate gets reduced
so sum will be
1.33-0.36=0.97
they gave reduction potential as 0.36 so oxidation is -0.36 and thts y i took -ve of that and added
 
histephenson007

histephenson007

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Sannikutti said:
well ya it was 1.33 but the formula is
some of oxidation potential and reduction potential
They said it oxidises the A to get lawsone
so chromate gets reduced
so sum will be
1.33-0.36=0.97
they gave reduction potential as 0.36 so oxidation is -0.36 and thts y i took -ve of that and added
Click to expand...
I don't get it, but that question was a goner anyway.
gud luck for ur other tests (y)
 
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