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Chemistry: Post your doubts here!

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w.r.t. H2O2 :
0.70/.05 = 1.4/1.0
7/5 = 7/5

w.r.t. H+ :
if we consider the conc of H2O2 first and compare it with rate:
0.09/0.05 = 1.8/1.0
9/5 = 9/5

it shows that the rate is changing just because of H2O2 .... which means that however much the conc of H+ changes, it won't have any effect on the rate of reaction. so wrt H+ the order of reaction is 0
Thanks a lot man, peace!
 
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Ekh I'm stuck with this too :/
it's a matter of the discharge priority stuff in electrlysis...
u know the reactivity series of metals that we did in O levels too?

so according to that, O2 is discharged in preference to SO4-2 and F- so it is discharged before F2 or SO2...
Br2 however is discharged in preference to O2.

similarly work with the reactivity series for metals... which will account for the discharge at the cathode.
 
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hey guys
how are u all?
i need a help in http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s12_qp_23.pdf Q3 c) , Q4 c) and f) ,Q5 c) and d)
waiting your help
thanks in advance
:)

did my best to explain. dont mind my writing. i was writing in on 'paints'
Q3 c
5512627700.png



4c
7113398496.png


4f
4958206357.png



5c

1552290363.png
 
Messages
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Points
523
really thank you for your help :) dont worry about the hand writing :p
can u plz also explain to me Q3 d) and Q 5 d)
and can u explain in more depth Q 5 C) the last step

i really appreciate your help :D

Wish u good luck

6264998407.png


Mole ratio is 1:1
so each mole of C3H6O3 will give 1 mole of H2
so you have mass of C3H6O3 so calculate moles and multiply it by 24000 so calculate volume of gas
See, 1 Moles occupy 24 dm3 (24000 Cm3) so you can even apply the cross wala method.
1 --- --------24000
6.67*10^3 -----x

x= 160 cm3



alcohols have hydrogen bonding between O and H so that it why they are polar and Hydrogen bond is stronger to hold the liquid particle while the DME gas compound has weak vander waals


and sorry i m weak in ester isomer. need to work on it

pls do pray for me.
 
Messages
297
Reaction score
696
Points
93
6264998407.png


Mole ratio is 1:1
so each mole of C3H6O3 will give 1 mole of H2
so you have mass of C3H6O3 so calculate moles and multiply it by 24000 so calculate volume of gas
See, 1 Moles occupy 24 dm3 (24000 Cm3) so you can even apply the cross wala method.
1 --- --------24000
6.67*10^3 -----x

x= 160 cm3



alcohols have hydrogen bonding between O and H so that it why they are polar and Hydrogen bond is stronger to hold the liquid particle while the DME gas compound has weak vander waals


and sorry i m weak in ester isomer. need to work on it

pls do pray for me.

Thank you,
Can u plz also check my other doubt ???
Wish u good luck
 
Messages
297
Reaction score
696
Points
93
6264998407.png


Mole ratio is 1:1
so each mole of C3H6O3 will give 1 mole of H2
so you have mass of C3H6O3 so calculate moles and multiply it by 24000 so calculate volume of gas
See, 1 Moles occupy 24 dm3 (24000 Cm3) so you can even apply the cross wala method.
1 --- --------24000
6.67*10^3 -----x

x= 160 cm3



alcohols have hydrogen bonding between O and H so that it why they are polar and Hydrogen bond is stronger to hold the liquid particle while the DME gas compound has weak vander waals


and sorry i m weak in ester isomer. need to work on it

pls do pray for me.
inshallah u will get the highest grade in all your subjects :)
 
Messages
859
Reaction score
360
Points
73
it's a matter of the discharge priority stuff in electrlysis...
u know the reactivity series of metals that we did in O levels too?

so according to that, O2 is discharged in preference to SO4-2 and F- so it is discharged before F2 or SO2...
Br2 however is discharged in preference to O2.

similarly work with the reactivity series for metals... which will account for the discharge at the cathode.
Could you by any chance explain this in terms of the electrode potential?
As in what are the equations for hydrogen & oxygen & do we need to change the sign for the electrode potential if the equation is reversed I.e in oxidation form?
 
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