We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
View attachment 52033
how is the ans B?
View attachment 52035
why isnt it C?
21/M/J/12
Question 5b(iii) Can some one please explain?
and in same Question c(ii) part they said use your information from b(i),b(ii) & c(i)..........
How can we use the part b(ii) answer to help us in this question????
thnk u HELPED A LOTFor 1, bromoethane from ethanol is a reaction that requires heating an alcohol under reflux, and then distilling off the halogenoalkane. The alcohol being ethanol here and the halogenoalkane formed being bromotethane.
The very fact that the halogenoalkane has to be distilled can confirm the necessity of having such a set up, since the halogenoalkane can be collected as a distillate in the flask attached to the end of the liebig condenser.
For 2, ethanal forming from ethanol is due to the oxidation of ethanol. This does require for the reaction mixture to be warmed before the oxidation takes place, and in the end you are also required to collect the aldehyde as a distillate.
For 3, 1,2-dibromoethane forming from bromine and ethene is done by bubbling an alkene through a solution of a halogen on the form X2.
So for 1.2-dibromoehane, it would simply have to be bubbled through a solution of bromine at room temperature ( aka no heating required ).
From all of the above options, the only two that require heating and distillation to take place are 1 and 2. Which is option B.
Hope that helped
Thanks a lot.Great Explanation1 molecule of X produces 2 hydrogen atoms. The hydrogen atoms come off of the -OH group as H+, leaving behind -ONa.
The reaction is, X + Na ---------> XNa + H2
The -OH group in X, has H replaced by Na. This gives 1 hydrogen atom.
In the products we have two hydrogen atoms, so there has to be another -OH group present.
------------------------------
I'm assuming when they say use your answer to b) ii) they're referring to the fact that 2 hydrogen atoms are formed. So X must have 2 hydrogen atoms.
However I find there's a much easier way to deducing the structure of X and it can probably save you a lot of time as well,
They tell you at the start the Mr of X is 90. The empirical formula of X being CH2O.
C = 12 g, H = 1 g, O = 16 g
Using the ratio of 1 C: 2 H : 1 O you get 12+2+16 = 30 g
You can use this to find out how much C, H and O contribute to 90 g.
90/30 * 1:2:1, since that is the ratio of C:H:O in the empirical formula.
This gives you C3H6O3 which is the molecular formula of X.
A chain of 3 carbons, CHO must be at the end of the chain. The 2 OH groups can be on the same carbon, or one on each.
You can then attach the remaining C and H atoms depending on where a bond can be made.
Route 1 ------> CH(OH)2CH2CHO
Route 2 ---------> CH2(OH)CH(OH)CHO
Route 3 -----------------> CH3C(OH)2CHO
Hope that helps
is it true that warm conc kmno4 doesn't react with alcohol at all?
Thanks for the help Buddy.........Question 1:
2 C14H30 + 43 O2 ----------> 28 CO2 + 30 H2O
1 tonne = 1000 kg
x tonnes = 10.8kg
x = 0.0108 tonnes for 1 km
For 8195 km = 8195 * 0.0108 = 88.506 tonnes
Molar mass of C14H30 = 198g ---> 0.198 kg ------->1.98 x 10^-4 tonnes
88.506 / 1.98 x 10^-4 = 447,000 moles of C14H30 used for 8195 km.
2 moles of C14H30 ----> 28 moles of CO2.
447,000 moles of C14H30 ------> x moles of CO2.
x = 6,258,000 moles of CO2 formed.
Mass of CO2 formed = moles of CO2 * molar mass of CO2 in tonnes
Molar mass of CO2 = 44g = 0.044 kg = 4.4 x 10^-5 tonnes
Mass of CO2 formed = (4.4 x 10^-5) * 6,258,000 =275.352 tonnes of CO2.
Which is basically 275 tonnes.
-------------------------------
reaction 1 is W ----> Z. First find Z,
This is Ca(OH)2 + H2SO4 ------> CaSO4 + 2H2O, Since Z is (s), it should be CaSO4.
W is Ca(NO3)2. Your goal is to go from Ca(NO3)2 -------> CaSO4.
So you end up with something like this,
Ca(NO3)2 + XSO4 ------> CaSO4 + X(NO3)2
or
Ca(NO3)2 + X2SO4 -------> CaSO4 + XNO3
The only two possible options for X in this case, are elements from group 1 and group 2.
Hope that helped!
21/O/N/09
Question 5 (d) help??????????
I usually face trouble when it comes to these types of questions any tips on how to do them????
Y is an organic compund. Y gives ppt aqueous silver nitrate. All of this ppt dissolves when concentrated ammonia is added. What is possible identity of Y ?
1- bromopropane
2-chlororethane
3-iodo-2-methylpropane
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now