may i know the answer pls?
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may i know the answer pls?
Yes that helped!N2O4 <--> 2NO2 at equilibrium.
Initially, there is 1 mol of N2O4. NO2 is yet to be formed.
When N2O4 dissociates, it gives 2 moles of NO2. 1:2
But it says in the question only 50% dissociates.
so 0.5 remains N2O4, and 0.5 dissociates.
This gives 1 mol of NO2 for every o.5 moles of N2O4. 0.5:1
Now with partial pressures there is something called a mole fraction. If you have the mole fraction, and the total pressure, you can find the partial pressure.
The formula is:
Mole fraction * Total pressure = Partial pressure
In the above reaction, there is 1 +0.5 = 1.5 mols in total.
N2O4 is 0.5/1.5 and NO2 is 1/1.5
This gives you 1/3 and 2/3.
Multiply these values by the total pressure, which is 1 in this case, and you get the partial pressures.
Partial pressure for N2O4 is 1/3 atm and 2/3 atm for NO2.
At equilibrium, there are 2 moles of NO2 for every 1 mole of N2O4.
so Kp = ( 2/3 )^2 / (1/3)^1
This gives you 4/3 atm.
Hope that helped ^_^
is 6 C,15 B?plz help !
plz help !
These are no longer Pentanones. You've used 6 carbons
These are no longer Pentanones. You've used 6 carbons
6 A and 15 Bis 6 C,15 B?
View attachment 52033
how is the ans B?
View attachment 52035
why isnt it C?
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